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Solve the following problem. Specific latent heat of vaporization of water is 2.26 × 106 J/kg. Calculate the energy needed to change 5.0 g of water into steam at 100 ºC. - Physics

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Question

Solve the following problem.

Specific latent heat of vaporization of water is 2.26 × 106 J/kg. Calculate the energy needed to change 5.0 g of water into steam at 100 ºC.

Sum
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Solution

Given: Lvap = 2.26 × 106 J/kg, m = 5g = 5 × 10-3 kg
In this case, no temperature change takes place an only a change of state occurs.

To find: Heat required to convert water into steam.

Formula: Heat required = mLvap 

Calculation: From formula,

Heat required = 5 × 10-3 × 2.26 × 10

= 11300 J

= 1.13 × 10J

Heat required to convert water into steam is 1.13 × 10J.

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Chapter 7: Thermal Properties of Matter - Exercises [Page 140]

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Balbharati Physics [English] Standard 11 Maharashtra State Board
Chapter 7 Thermal Properties of Matter
Exercises | Q 3. (iii) | Page 140
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