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Karnataka Board PUCPUC Science Class 11

An Electric Field → E = → I Ax Exists in Space, Where a = 10 V M−2. Take the Potential at (10 M, 20 M) to Be Zero. Find the Potential at the Origin.

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Question

An electric field  \[\vec{E}  =  \vec{i}\]  Ax exists in space, where A = 10 V m−2. Take the potential at (10 m, 20 m) to be zero. Find the potential at the origin.

Numerical
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Solution

Given:
Electric field intensity, 

\[\vec{E}  =  \hat{ i } \text{Ax} = 10\text{ x } \hat{i} \]

Potential,

\[dV =  -  \vec{E}  .    \vec{\text{dx}}  =  - 10\text{xdx}\]

On integrating, we get

\[V = 10 \times \frac{x^2}{2} =  -  \left[ 5 x^2 \right]_{10}^0 \] 

\[V = 5 \times 100 = 500 \] V

So, at the origin, the potential is 500 V.

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Chapter 29: Electric Field and Potential - Exercises [Page 123]

APPEARS IN

HC Verma Concepts of Physics Volume 1 and 2 [English]
Chapter 29 Electric Field and Potential
Exercises | Q 59 | Page 123

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