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Karnataka Board PUCPUC Science Class 11

A Particle of Mass 1 G and Charge 2.5 × 10−4 C is Released from Rest in an Electric Field of 1.2 × 10 4 N C−1. What Will Be the Speed of the Particle After Travelling this Distance? - Physics

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Question

A particle of mass 1 g and charge 2.5 × 10−4 C is released from rest in an electric field of 1.2 × 10 4 N C−1. What will be the speed of the particle after travelling this distance? 

Short/Brief Note
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Solution

Given:
Charge of the particle, q = 2.5 × 10−4 C
Initial velocity, u = 0 
Electric field intensity, E = 1.2 × 104 N/C
Mass of the particle, m = 1 g = 10−3 kg
Distance travelled, s = 40 cm = 4 × 10−1 m

 Using the third equation of motion, we get

\[v^2  =  u^2  + 2as\] 

\[ \Rightarrow  v^2  = 0 + 2 \times 3 \times  {10}^3  \times 4 \times  {10}^{- 1} \] 

\[ \Rightarrow v = 4 . 9 \times 10 = 49  \text{ m/s }\]

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Chapter 7: Electric Field and Potential - Exercises [Page 122]

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HC Verma Concepts of Physics Vol. 2 [English] Class 11 and 12
Chapter 7 Electric Field and Potential
Exercises | Q 48.3 | Page 122

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