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An A.P. consists of 50 terms of which 3rd term is 12 and the last term is 106. Find the 29th term of the A.P. - Mathematics

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Question

An A.P. consists of 50 terms of which 3rd term is 12 and the last term is 106. Find the 29th term of the A.P.

Sum
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Solution

Given that,

a3 = 12

a50 = 106

We know that,

an = a + (n − 1)d

a3 = a + (3 − 1)d

12 = a + 2d             ...(i)

Similarly, a50 = a + (50 − 1)d

106 = a + 49d        ...(ii)

On subtracting (i) from (ii), we obtain

94 = 47d

d = 2

From equation (i), we obtain

12 = a + 2(2)

a = 12 − 4

a = 8

a29 = a + (29 − 1)d

a29 = 8 + (28)2

a29 = 8 + 56

a29 = 64

Therefore, 29th term is 64.

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Chapter 5: Arithmetic Progressions - EXERCISE 5.2 [Page 62]

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NCERT Mathematics [English] Class 10
Chapter 5 Arithmetic Progressions
EXERCISE 5.2 | Q 8. | Page 62

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