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Karnataka Board PUCPUC Science 2nd PUC Class 12

Alcohols react with active metals e.g. Na, K etc. to give corresponding alkoxides. Write down the decreasing order of reactivity of sodium metal towards primary, secondary and tertiary alcohols.

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Question

Alcohols react with active metals e.g. Na, K etc. to give corresponding alkoxides. Write down the decreasing order of reactivity of sodium metal towards primary, secondary and tertiary alcohols.

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Solution

Decreasing order of reactivity of sodium metal is:

1° > 2° > 3°

Alcohols react with sodium metal to form alkoxides and hydrogen is liberated:

\[\ce{R - O - H + Na -> RO - Na+ {+} 1/2 H2}\]

The order of reactivity of alcohols is primary > secondary > tertiary. This can be explained on the basis of cleavage of O – H bond. The alkyl groups are electron releasing groups (+I effect) and they increase the electron density around the oxygen. As a result, the electrons of O – H bond cannot be withdrawn strongly towards oxygen and O – H remains strong. Therefore, greater is the number, of alkyl groups present, smaller will be reactivity of alcohol.

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Chapter 11: Alcohols, Phenols and Ethers - Multiple Choice Questions (Type - I) [Page 159]

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NCERT Exemplar Chemistry Exemplar [English] Class 12
Chapter 11 Alcohols, Phenols and Ethers
Multiple Choice Questions (Type - I) | Q 35 | Page 159

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