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Question
Account for the following:
Glucose is a reducing sugar
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Solution
Glucose reduces Fehlings reagent
\[\begin{array}{cc}
\phantom{..}\ce{H}\phantom{...}\ce{O}\phantom{.........................}\ce{HO}\phantom{...}\ce{O}\phantom{...............}\\
\phantom{..}\backslash\phantom{..}//\phantom{............................}\backslash\phantom{..}//\phantom{..............}\\
\phantom{.}\ce{C}\phantom{...............................}\ce{C}\phantom{..............}\\
\phantom{..}|\phantom{................................}|\phantom{...............}\\
\phantom{.}\ce{H-C-OH}\phantom{.......................}\ce{H-C-OH}\phantom{............}\\
\phantom{......}|\phantom{................................}|\phantom{...................}\\
\phantom{.}\ce{HO-C-H + 2Cu^{2+} + 2H2O -> HO-C-H + Cu2O + 4H+}\\
\phantom{.}|\phantom{................................}|\phantom{..............}\\
\phantom{..}\ce{H-C-OH}\phantom{......................}\ce{H-C-OH}\phantom{.............}\\
\phantom{..}|\phantom{................................}|\phantom{...............}\\
\phantom{..}\ce{H-C-OH}\phantom{......................}\ce{H-C-OH}\phantom{.............}\\
\phantom{..}|\phantom{................................}|\phantom{...............}\\
\phantom{......}\ce{CH2OH}\phantom{.........................}\ce{CH2OH}\phantom{.............}
\end{array}\]
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RELATED QUESTIONS
Glucose or sucrose are soluble in water but cyclohexane or benzene (simple six membered ring compounds) are insoluble in water. Explain.
Write two main functions of carbohydrates in plants.
Classify the following into monosaccharides and disaccharides.
Ribose, 2-deoxyribose, maltose, galactose, fructose and lactose
The number of primary and secondary hydroxyl groups in ribose are -
(a) 1, 3
(b) 2, 3
(c) 3, 1
(d) 3, 2
Glycosidic linkage is found between ____________.
Monosaccharides usually contains ____________ carbon atoms.
Reducing sugars reduce ____________.
The pair of compounds in which both the compounds give the positive test with Tollen’s reagent is:
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Assertion: Deoxyribose, \[\ce{C5H10O4}\] is not a carbohydrate.
Reason: Carbohydrates are hydrates of carbon so compounds which follow \[\ce{C_x(H2O)_y}\] formula are carbohydrates.
