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Question
Account for the following:
Aniline does not undergo Friedel-Crafts reaction.
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Solution
Aniline being a Lewis base reacts with Lewis acid AlCl3 to form a salt.
\[\ce{C6H5\overset{\bullet\bullet}{N}H2 + AlCl3 -> C6H5\overset{+}{N}H2AlCl^-_3}\]
Due to the presence of a positive charge on N-atom in the salt, the group \[\ce{-\overset{+}{N}H2AlCl^-_3}\] acts as a strongly deactivating group. As a result, it reduces the electron density in the benzene ring and inhibits the electrophilic substitution reaction. Therefore, aniline does not undergo the Friedel-Crafts reaction.
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Which of the following reaction is not correct.
‘A’ is:
C5H13N reacts with HNO2 to give an optically active compound – The compound is ____________.
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How will you convert nitrobenzene into aniline?
Identify compounds A, B and C in the following sequence of reaction.
\[\ce{C6H5NO2 ->[Fe/HCl] A ->[HNO2][273 K] B ->[C6H5OH] C}\]
Write a short note on the following.
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Arrange the following.
In increasing order of basic strength aniline, p-toluidine and p-nitro aniline
Account for the following
Aniline does not undergo Friedel–Crafts reaction
Account for the following.
Aniline does not undergo Friedel–Crafts reaction
