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प्रश्न
Account for the following:
Aniline does not undergo Friedel-Crafts reaction.
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उत्तर
Aniline being a Lewis base reacts with Lewis acid AlCl3 to form a salt.
\[\ce{C6H5\overset{\bullet\bullet}{N}H2 + AlCl3 -> C6H5\overset{+}{N}H2AlCl^-_3}\]
Due to the presence of a positive charge on N-atom in the salt, the group \[\ce{-\overset{+}{N}H2AlCl^-_3}\] acts as a strongly deactivating group. As a result, it reduces the electron density in the benzene ring and inhibits the electrophilic substitution reaction. Therefore, aniline does not undergo the Friedel-Crafts reaction.
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Which one of the following will not undergo Hofmann bromamide reaction?
\[\ce{CH3CH2Br ->[aq NaOH][\Delta] A ->[KMnO4/H^+][\Delta] B ->[NH3][\Delta] C ->[Br2/NaOH] D}\] ‘D’ is:
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Identify compounds A, B and C in the following sequence of reaction.
\[\ce{C6H5NO2 ->[Fe/HCl] A ->[HNO2][273 K] B ->[C6H5OH] C}\]
Arrange the following.
In increasing order of basic strength C6H5NH2, C6H5NHCH3, C6H5NH2, p-Cl-C6H4-NH2
Identify A, B and C.
Account for the following.
Aniline does not undergo Friedel–Crafts reaction
Account for the following.
Aniline does not undergo Friedel – Crafts reaction.
