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Question
Accomplish the following conversion:
Aniline to p-bromoaniline
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Solution
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RELATED QUESTIONS
Identify the weakest base amongst the following :
(a) p- methoxyaniline
(b) o-toluidine
(c) benzene - 1, 4 - diamine
(d) 4 - aminobenzoic acid
Arrange the following in increasing order of their basic strength :
C6H5 – NH2, C6H5 – CH2 – NH2, C6H5 – NH – CH3
- Write structures of different isomeric amines corresponding to the molecular formula C4H11N.
- Write the IUPAC names of all the isomers.
- What type of isomerism is exhibited by different pairs of amines?
How will you convert Benzene into aniline?
How will you convert Cl−(CH2)4−Cl into hexan-1, 6-diamine?
Account for the following:
Gabriel phthalimide synthesis is preferred for synthesising primary amines.
Arrange the following:
In increasing order of boiling point:
C2H5OH, (CH3)2NH, C2H5NH2
Write a short note on ammonolysis.
Give reasons CH3NH2 is more basic than C6H5NH2.
Arrange the following in the increasing order of their pKb values:
C6H5NH2, C2H5NH2, C6H5NHCH3
Illustrate the following reactions giving suitable example in each case
Ammonolysis
Arrange the following in increasing order of basic strength :
C6H5NH2, C6H5NHCH3, C6H5N(CH3)2
Answer in one sentence.
Arrange the following amines in increasing order of boiling points.
n-propylamine, ethylmethyl amine, trimethylamine.
The CORRECT decreasing order of boiling points is:
Among the following isomeric amines, an amine having highest boiling point is:
A compound Z with molecular formula \[\ce{C3H9N}\] reacts with \[\ce{C6H5SO2Cl}\] to give a solid, insoluble in alkali. Identify Z.
Assertion: N-Ethylbenzene sulphonamide is soluble in alkali.
Reason: Hydrogen attached to nitrogen in sulphonamide is strongly acidic.
Which of the following compound gives a secondary amine oh reduction?
Which of the following amines form maximum hydrogen bonds within themselves?
Arrange the following in increasing order of their boiling point:
C2H5OH, C2H5NH2, (C2H5)3N
