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Question
Arrange the following in increasing order of their basic strength :
C6H5 – NH2, C6H5 – CH2 – NH2, C6H5 – NH – CH3
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Solution
C6H5-NH2 < C6H5-NH-CH3 < C6H5-CH2-NH2
Reason:-
C6H5-NH2 will be least basic because of the delocalisation of the lone pair of electrons present on the N-atom over the benzene ring due to the ‒R effect of the C6H5 group. However, C6H5-CH2-NH2 will be more basic than C6H5-NH-CH3 because of the electron-releasing nature of the CH3- group that increases the electron density on the N-atom, making the lone pair of electrons on the N-atom easily available for donation to a proton. The basicity of C6H5-NH-CH3 will be intermediate of C6H5-NH2 and C6H5-CH2-NH2 because the C6H5- group will tend to pull the electron density from the N-atom. On the other hand the CH3- group will tend to increase the electron density on the N-atom. Thus, the basic strength of the given amines will follow the above-mentioned order.
RELATED QUESTIONS
Identify the weakest base amongst the following :
(a) p- methoxyaniline
(b) o-toluidine
(c) benzene - 1, 4 - diamine
(d) 4 - aminobenzoic acid
Give reason for the following:
Primary amines have higher boiling point than tertiary amines.
Arrange the following in increasing order of their basic strength :

Arrange the following in increasing order of their basic strength:
C2H5NH2, (C2H5)2NH, (C2H5)3N, C6H5NH2
Arrange the following:
In increasing order of boiling point:
C2H5OH, (CH3)2NH, C2H5NH2
Complete the following reaction:
\[\ce{C6H5N2Cl + H3PO2 + H2O ->}\]
Answer in one sentence.
Arrange the following amines in increasing order of boiling points.
n-propylamine, ethylmethyl amine, trimethylamine.
Among the following isomeric amines, an amine having highest boiling point is:
Dimerisation of carboxylic acids is due to
Arrange the decreasing boiling point.
\[\ce{CH3COOH, C2H5OH, CH3NH2, CH3OCH3}\]
