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Question
Arrange the following in increasing order of their basic strength :
C6H5 – NH2, C6H5 – CH2 – NH2, C6H5 – NH – CH3
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Solution
C6H5-NH2 < C6H5-NH-CH3 < C6H5-CH2-NH2
Reason:-
C6H5-NH2 will be least basic because of the delocalisation of the lone pair of electrons present on the N-atom over the benzene ring due to the ‒R effect of the C6H5 group. However, C6H5-CH2-NH2 will be more basic than C6H5-NH-CH3 because of the electron-releasing nature of the CH3- group that increases the electron density on the N-atom, making the lone pair of electrons on the N-atom easily available for donation to a proton. The basicity of C6H5-NH-CH3 will be intermediate of C6H5-NH2 and C6H5-CH2-NH2 because the C6H5- group will tend to pull the electron density from the N-atom. On the other hand the CH3- group will tend to increase the electron density on the N-atom. Thus, the basic strength of the given amines will follow the above-mentioned order.
RELATED QUESTIONS
- Write structures of different isomeric amines corresponding to the molecular formula C4H11N.
- Write the IUPAC names of all the isomers.
- What type of isomerism is exhibited by different pairs of amines?
How will you convert Benzene into aniline?
Complete the following acid-base reaction and name the product:
\[\ce{(C2H5)3N + HCl ->}\]
Accomplish the following conversion:
Benzene to m-bromophenol
Arrange the following compounds in increasing order of their boiling points.
Ethyl alcohol, Ethyl amine, Ethanoic acid, Ethane
Which of the following should be most volatile?
Assertion: N-Ethylbenzene sulphonamide is soluble in alkali.
Reason: Hydrogen attached to nitrogen in sulphonamide is strongly acidic.
Dimerisation of carboxylic acids is due to
Arrange the decreasing boiling point.
\[\ce{CH3COOH, C2H5OH, CH3NH2, CH3OCH3}\]
Write short note on the following:
Ammonolysis
