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प्रश्न
Arrange the following in increasing order of their basic strength :
C6H5 – NH2, C6H5 – CH2 – NH2, C6H5 – NH – CH3
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उत्तर
C6H5-NH2 < C6H5-NH-CH3 < C6H5-CH2-NH2
Reason:-
C6H5-NH2 will be least basic because of the delocalisation of the lone pair of electrons present on the N-atom over the benzene ring due to the ‒R effect of the C6H5 group. However, C6H5-CH2-NH2 will be more basic than C6H5-NH-CH3 because of the electron-releasing nature of the CH3- group that increases the electron density on the N-atom, making the lone pair of electrons on the N-atom easily available for donation to a proton. The basicity of C6H5-NH-CH3 will be intermediate of C6H5-NH2 and C6H5-CH2-NH2 because the C6H5- group will tend to pull the electron density from the N-atom. On the other hand the CH3- group will tend to increase the electron density on the N-atom. Thus, the basic strength of the given amines will follow the above-mentioned order.
संबंधित प्रश्न
Give reasons for the following: (CH3)2NH is more basic than (CH3)3N in an aqueous solution.
Give reason for the following:
Primary amines have higher boiling point than tertiary amines.
Arrange the following in increasing order of their basic strength:
CH3NH2, (CH3)2NH, (CH3)3N, C6H5NH2, C6H5CH2NH2
Account for the following:
Gabriel phthalimide synthesis is preferred for synthesising primary amines.
Write a short note on ammonolysis.
Accomplish the following conversion:
Benzene to m-bromophenol
Give reason (CH3)2NH is more basic than (CH3)3N in an aqueous solution.
The CORRECT decreasing order of solubility in water will be ____________.
Which among the following has the highest boiling point?
Arrange the decreasing boiling point.
\[\ce{CH3COOH, C2H5OH, CH3NH2, CH3OCH3}\]
