Advertisements
Advertisements
प्रश्न
Give reason (CH3)2NH is more basic than (CH3)3N in an aqueous solution.
Advertisements
उत्तर
With the increase in the alkyl group, the +I effect will increase which will increase the ease of donation of lone pair electron. But in water, one other factor is controlling the strength of basicity.
Amine will accept a proton and form the cation. This cation will be stabilised in water by solvation (by hydrogen bonding). Better the solvation by hydrogen bonding, higher will be the basic strength.
Thus with the increase in methyl group, hydrogen bonding and stabilisation by solvation decreases. The net effect is when we move from secondary to tertiary amine basic strength actually decreases.
APPEARS IN
संबंधित प्रश्न
Arrange the following: C2H5NH2, C2H5OH, (CH3)3N – in the increasing order of their boiling point
Complete the following acid-base reaction and name the product:
\[\ce{(C2H5)3N + HCl ->}\]
Write a short note on ammonolysis.
Complete the following reaction:
\[\ce{C6H5N2Cl + H3PO2 + H2O ->}\]
Give reasons CH3NH2 is more basic than C6H5NH2.
Illustrate the following reactions giving suitable example in each case
Ammonolysis
Tertiary amines have lowest boiling points because ________________
Which of the following should be most volatile?
A compound Z with molecular formula \[\ce{C3H9N}\] reacts with \[\ce{C6H5SO2Cl}\] to give a solid, insoluble in alkali. Identify Z.
Which one of the following compounds will liberate CO2, when treated with NaHCO3?
