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प्रश्न
A compound Z with molecular formula \[\ce{C3H9N}\] reacts with \[\ce{C6H5SO2Cl}\] to give a solid, insoluble in alkali. Identify Z.
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उत्तर
Z is an aliphatic amine which gives a solid insoluble in base. This implies that reaction with \[\ce{C6H5SO2Cl}\] must give a product without any replaceable hydrogen attached to nitrogen. In other words, the amine must be a secondary amine. i.e. Z is ethylmethylamine.
\[\begin{array}{cc}
\ce{O}\phantom{.......}\\
||\phantom{.......}\\
\phantom{}\ce{CH3 - NH + C6H5 - S - Cl -> CH3N - SO2C6H5}\phantom{.}\\
\phantom{..}|\phantom{.............}||\phantom{...............}|\phantom{.......}\\
\phantom{.......}\ce{C2H5}\phantom{.........}\ce{O}\phantom{......}\ce{\underset{sulphonamide}{\underset{N-Ethyl-N-methyl benzene}{C2H5}}\phantom{.}}
\end{array}\]
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संबंधित प्रश्न
Identify the weakest base amongst the following :
(a) p- methoxyaniline
(b) o-toluidine
(c) benzene - 1, 4 - diamine
(d) 4 - aminobenzoic acid
Give reasons for the following: (CH3)2NH is more basic than (CH3)3N in an aqueous solution.
Arrange the following: C2H5NH2, C2H5OH, (CH3)3N – in the increasing order of their boiling point
Arrange the following in increasing order of their basic strength :
C6H5 – NH2, C6H5 – CH2 – NH2, C6H5 – NH – CH3
How will you convert Benzene into aniline?
Complete the following acid-base reaction and name the product:
\[\ce{CH3CH2CH2NH2 + HCl ->}\]
Complete the following acid-base reaction and name the product:
\[\ce{(C2H5)3N + HCl ->}\]
Arrange the following:
In increasing order of boiling point:
C2H5OH, (CH3)2NH, C2H5NH2
Give reasons CH3NH2 is more basic than C6H5NH2.
Arrange the following in the increasing order of their pKb values:
C6H5NH2, C2H5NH2, C6H5NHCH3
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Which among the following has the highest boiling point?
The CORRECT decreasing order of boiling points is:
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The hydrogen bond is shortest in
Which of the following compound gives a secondary amine oh reduction?
Which of the following have less melting point than amine?
Write short note on the following:
Ammonolysis
