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प्रश्न
A compound Z with molecular formula \[\ce{C3H9N}\] reacts with \[\ce{C6H5SO2Cl}\] to give a solid, insoluble in alkali. Identify Z.
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उत्तर
Z is an aliphatic amine which gives a solid insoluble in base. This implies that reaction with \[\ce{C6H5SO2Cl}\] must give a product without any replaceable hydrogen attached to nitrogen. In other words, the amine must be a secondary amine. i.e. Z is ethylmethylamine.
\[\begin{array}{cc}
\ce{O}\phantom{.......}\\
||\phantom{.......}\\
\phantom{}\ce{CH3 - NH + C6H5 - S - Cl -> CH3N - SO2C6H5}\phantom{.}\\
\phantom{..}|\phantom{.............}||\phantom{...............}|\phantom{.......}\\
\phantom{.......}\ce{C2H5}\phantom{.........}\ce{O}\phantom{......}\ce{\underset{sulphonamide}{\underset{N-Ethyl-N-methyl benzene}{C2H5}}\phantom{.}}
\end{array}\]
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संबंधित प्रश्न
Give reasons for the following: (CH3)2NH is more basic than (CH3)3N in an aqueous solution.
Arrange the following: C2H5NH2, C2H5OH, (CH3)3N – in the increasing order of their boiling point
Arrange the following in increasing order of their basic strength :
C6H5 – NH2, C6H5 – CH2 – NH2, C6H5 – NH – CH3
How will you convert Cl−(CH2)4−Cl into hexan-1, 6-diamine?
Complete the following acid-base reaction and name the product:
\[\ce{CH3CH2CH2NH2 + HCl ->}\]
Account for the following:
Gabriel phthalimide synthesis is preferred for synthesising primary amines.
Write a short note on ammonolysis.
Accomplish the following conversion:
Benzene to m-bromophenol
Give a plausible explanation for the following:
Why are aliphatic amines stronger bases than aromatic amines?
Give reasons CH3NH2 is more basic than C6H5NH2.
Tertiary amines have lowest boiling points because ________________
The CORRECT decreasing order of solubility in water will be ____________.
Which among the following has the highest boiling point?
Assertion: N-Ethylbenzene sulphonamide is soluble in alkali.
Reason: Hydrogen attached to nitrogen in sulphonamide is strongly acidic.
Which of the following have less melting point than amine?
Which of the following amines form maximum hydrogen bonds within themselves?
The correct order of decreasing basic strength of the given amines is:
