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प्रश्न
Account for the following:
Gabriel phthalimide synthesis is preferred for synthesising primary amines.
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उत्तर
Gabriel phthalimide synthesis results in the formation of 1° amine only. 2° or 3° amines are not formed in this synthesis. Thus, a pure 1° amine can be obtained. Therefore, Gabriel phthalimide synthesis is preferred for synthesizing primary amines.
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संबंधित प्रश्न
Give reason for the following:
Primary amines have higher boiling point than tertiary amines.
Arrange the following in increasing order of their basic strength :
C6H5 – NH2, C6H5 – CH2 – NH2, C6H5 – NH – CH3
Arrange the following in increasing order of their basic strength :
- Write structures of different isomeric amines corresponding to the molecular formula C4H11N.
- Write the IUPAC names of all the isomers.
- What type of isomerism is exhibited by different pairs of amines?
How will you convert Cl−(CH2)4−Cl into hexan-1, 6-diamine?
Arrange the following in increasing order of their basic strength:
C2H5NH2, C6H5NH2, NH3, C6H5CH2NH2 and (C2H5)2NH
Complete the following acid-base reaction and name the product:
\[\ce{CH3CH2CH2NH2 + HCl ->}\]
Complete the following acid-base reaction and name the product:
\[\ce{(C2H5)3N + HCl ->}\]
Write a short note on ammonolysis.
Complete the following reaction:
\[\ce{C6H5N2Cl + H3PO2 + H2O ->}\]
Give reasons CH3NH2 is more basic than C6H5NH2.
Choose the most correct option.
Which one of the following compounds has the highest boiling point?
Answer in one sentence.
Arrange the following amines in increasing order of boiling points.
n-propylamine, ethylmethyl amine, trimethylamine.
Tertiary amines have lowest boiling points because ________________
A compound Z with molecular formula \[\ce{C3H9N}\] reacts with \[\ce{C6H5SO2Cl}\] to give a solid, insoluble in alkali. Identify Z.
Which one of the following compounds will liberate CO2, when treated with NaHCO3?
The correct order of decreasing basic strength of the given amines is:
