Advertisements
Advertisements
प्रश्न
Complete the following reaction:
\[\ce{C6H5N2Cl + H3PO2 + H2O ->}\]
Advertisements
उत्तर
\[\ce{\underset{chloride}{\underset{Benzenediazonium}{C6H5N2Cl}} + H3PO2 + H2O ->[Cu+][Reduction] \underset{Benzene}{C6H6} + N2 + H3PO3 + HCl}\]
APPEARS IN
संबंधित प्रश्न
Give reason for the following:
Primary amines have higher boiling point than tertiary amines.
Arrange the following in increasing order of their basic strength :
How will you convert Cl−(CH2)4−Cl into hexan-1, 6-diamine?
Arrange the following in increasing order of their basic strength:
C2H5NH2, (C2H5)2NH, (C2H5)3N, C6H5NH2
Accomplish the following conversion:
Benzene to m-bromophenol
Accomplish the following conversion:
Aniline to p-bromoaniline
Give reason (CH3)2NH is more basic than (CH3)3N in an aqueous solution.
Answer in one sentence.
Arrange the following amines in increasing order of boiling points.
n-propylamine, ethylmethyl amine, trimethylamine.
Arrange the following compounds in increasing order of their boiling points.
Ethyl alcohol, Ethyl amine, Ethanoic acid, Ethane
The CORRECT decreasing order of boiling points is:
A compound Z with molecular formula \[\ce{C3H9N}\] reacts with \[\ce{C6H5SO2Cl}\] to give a solid, insoluble in alkali. Identify Z.
Assertion: N-Ethylbenzene sulphonamide is soluble in alkali.
Reason: Hydrogen attached to nitrogen in sulphonamide is strongly acidic.
Account for the following:
N-ethylethanamine boils at 329.3 K and butanamine boils at 350.8 K, although both are isomeric in nature.
The hydrogen bond is shortest in
Which of the following amines form maximum hydrogen bonds within themselves?
Which one of the following compounds will liberate CO2, when treated with NaHCO3?
Arrange the decreasing boiling point.
\[\ce{CH3COOH, C2H5OH, CH3NH2, CH3OCH3}\]
Write short note on the following:
Ammonolysis
