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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Complete the following reaction: C6H5NH2 + CHCl3 + alc. KOH -> - Chemistry

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प्रश्न

Complete the following reaction:

\[\ce{C6H5NH2 + CHCl3 + alc. KOH ->}\]

रासायनिक समीकरण/संरचनाएँ
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उत्तर

\[\ce{\underset{Aniline}{C6H5NH2} + CHCl3 + 3KOH (alc.) ->[\Delta][Carbylamine reaction] 3H2O + 3KCl + \underset{phenyl isocyanide}{C6H5 - NC}}\]

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अध्याय 9: Amines - Exercises [पृष्ठ २८०]

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एनसीईआरटी Chemistry Part 1 and 2 [English] Class 12
अध्याय 9 Amines
Exercises | Q 9.11 (i) | पृष्ठ २८०

संबंधित प्रश्न

Which of the following amines yields foul smelling product with holoform and alcoholic KOH?

(a)    Ethyl amine                   

(b)   Diethyl amine

(c)    Triethyi amine               

(d)  Ethyl methyl amine


Write the chemical equations involved in the following reactions:

Carbylamine reaction


Write the chemical equations involved when aniline is treated with the following reagents:

CHCI3 + KOH


Give a simple chemical test to distinguish between Aniline and N, N-dimethylaniline


Give a balanced equation for the following name reaction:

Carbylamine reaction


Write equations of the following reactions:
Carbyl amine reaction


Which one of the following shows the carbylamine reaction in the presence of heat?


A primary amine, \[\ce{RNH2}\] can be reacted with \[\ce{CH3-X}\] to get secondary amine, \[\ce{R-NHCH3}\] but the only disadvantage is that 3° amine and quaternary ammonium salts are also obtained as side products. Can you suggest a method where \[\ce{RNH2}\] forms only 2° amine?


Assertion: Acetanilide is less basic than aniline.

Reason: Acetylation of aniline results in decrease of electron density on nitrogen.


What happens when reaction:

Aniline reacts with chloroform in the presence of alcoholic potassium hydroxide


Aniline and diphenylamine may be distinguished by ______.


What is the action of the following reagents on ethyl amine?

Chloroform and caustic potash


The reaction of a primary amine with chloroform and ethanolic KOH is called ______.


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