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प्रश्न
A compound Z with molecular formula \[\ce{C3H9N}\] reacts with \[\ce{C6H5SO2Cl}\] to give a solid, insoluble in alkali. Identify Z.
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उत्तर
Z is an aliphatic amine which gives a solid insoluble in base. This implies that reaction with \[\ce{C6H5SO2Cl}\] must give a product without any replaceable hydrogen attached to nitrogen. In other words, the amine must be a secondary amine. i.e. Z is ethylmethylamine.
\[\begin{array}{cc}
\ce{O}\phantom{.......}\\
||\phantom{.......}\\
\phantom{}\ce{CH3 - NH + C6H5 - S - Cl -> CH3N - SO2C6H5}\phantom{.}\\
\phantom{..}|\phantom{.............}||\phantom{...............}|\phantom{.......}\\
\phantom{.......}\ce{C2H5}\phantom{.........}\ce{O}\phantom{......}\ce{\underset{sulphonamide}{\underset{N-Ethyl-N-methyl benzene}{C2H5}}\phantom{.}}
\end{array}\]
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संबंधित प्रश्न
Give reason for the following:
Primary amines have higher boiling point than tertiary amines.
- Write structures of different isomeric amines corresponding to the molecular formula C4H11N.
- Write the IUPAC names of all the isomers.
- What type of isomerism is exhibited by different pairs of amines?
Arrange the following in increasing order of their basic strength:
C2H5NH2, C6H5NH2, NH3, C6H5CH2NH2 and (C2H5)2NH
Arrange the following in increasing order of their basic strength:
CH3NH2, (CH3)2NH, (CH3)3N, C6H5NH2, C6H5CH2NH2
Complete the following acid-base reaction and name the product:
\[\ce{CH3CH2CH2NH2 + HCl ->}\]
Complete the following acid-base reaction and name the product:
\[\ce{(C2H5)3N + HCl ->}\]
Account for the following:
Gabriel phthalimide synthesis is preferred for synthesising primary amines.
Accomplish the following conversion:
Aniline to p-bromoaniline
Give reasons CH3NH2 is more basic than C6H5NH2.
Arrange the following in the increasing order of their pKb values:
C6H5NH2, C2H5NH2, C6H5NHCH3
Choose the most correct option.
Which one of the following compounds has the highest boiling point?
Which of the following should be most volatile?
Assertion: N-Ethylbenzene sulphonamide is soluble in alkali.
Reason: Hydrogen attached to nitrogen in sulphonamide is strongly acidic.
Account for the following:
N-ethylethanamine boils at 329.3 K and butanamine boils at 350.8 K, although both are isomeric in nature.
Dimerisation of carboxylic acids is due to
Which of the following compound gives a secondary amine oh reduction?
Which of the following have less melting point than amine?
Arrange the decreasing boiling point.
\[\ce{CH3COOH, C2H5OH, CH3NH2, CH3OCH3}\]
The correct order of decreasing basic strength of the given amines is:
