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प्रश्न
Complete the following acid-base reaction and name the product:
\[\ce{CH3CH2CH2NH2 + HCl ->}\]
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उत्तर
\[\ce{\underset{n-Propylamine}{CH3CH2CH2NH2} + HCl -> \underset{n-Propylammonium chloride}{CH3CH2CH2\overset{+}{N}H3Cl-}}\]
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संबंधित प्रश्न
Identify the weakest base amongst the following :
(a) p- methoxyaniline
(b) o-toluidine
(c) benzene - 1, 4 - diamine
(d) 4 - aminobenzoic acid
Give reason for the following:
Primary amines have higher boiling point than tertiary amines.
Arrange the following: C2H5NH2, C2H5OH, (CH3)3N – in the increasing order of their boiling point
Arrange the following in increasing order of their basic strength :
How will you convert Cl−(CH2)4−Cl into hexan-1, 6-diamine?
Write a short note on ammonolysis.
Give reasons CH3NH2 is more basic than C6H5NH2.
Illustrate the following reactions giving suitable example in each case
Ammonolysis
Choose the most correct option.
Which one of the following compounds has the highest boiling point?
Tertiary amines have lowest boiling points because ________________
Which among the following has the highest boiling point?
Which of the following should be most volatile?
Account for the following:
N-ethylethanamine boils at 329.3 K and butanamine boils at 350.8 K, although both are isomeric in nature.
Acetic acid exist as dimer in benzene due to
Dimerisation of carboxylic acids is due to
Which of the following have less melting point than amine?
Which one of the following compounds will liberate CO2, when treated with NaHCO3?
Arrange the decreasing boiling point.
\[\ce{CH3COOH, C2H5OH, CH3NH2, CH3OCH3}\]
