Advertisements
Advertisements
प्रश्न
Give reason (CH3)2NH is more basic than (CH3)3N in an aqueous solution.
Advertisements
उत्तर
With the increase in the alkyl group, the +I effect will increase which will increase the ease of donation of lone pair electron. But in water, one other factor is controlling the strength of basicity.
Amine will accept a proton and form the cation. This cation will be stabilised in water by solvation (by hydrogen bonding). Better the solvation by hydrogen bonding, higher will be the basic strength.
Thus with the increase in methyl group, hydrogen bonding and stabilisation by solvation decreases. The net effect is when we move from secondary to tertiary amine basic strength actually decreases.
APPEARS IN
संबंधित प्रश्न
Arrange the following in increasing order of their basic strength :
C6H5 – NH2, C6H5 – CH2 – NH2, C6H5 – NH – CH3
Arrange the following in increasing order of their basic strength:
C2H5NH2, (C2H5)2NH, (C2H5)3N, C6H5NH2
Arrange the following in increasing order of their basic strength:
CH3NH2, (CH3)2NH, (CH3)3N, C6H5NH2, C6H5CH2NH2
Account for the following:
Gabriel phthalimide synthesis is preferred for synthesising primary amines.
Complete the following reaction:
\[\ce{C6H5N2Cl + H3PO2 + H2O ->}\]
Illustrate the following reactions giving suitable example in each case
Ammonolysis
Which among the following has the highest boiling point?
Which of the following should be most volatile?
The hydrogen bond is shortest in
Which of the following amines form maximum hydrogen bonds within themselves?
