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प्रश्न
Give reason (CH3)2NH is more basic than (CH3)3N in an aqueous solution.
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उत्तर
With the increase in the alkyl group, the +I effect will increase which will increase the ease of donation of lone pair electron. But in water, one other factor is controlling the strength of basicity.
Amine will accept a proton and form the cation. This cation will be stabilised in water by solvation (by hydrogen bonding). Better the solvation by hydrogen bonding, higher will be the basic strength.
Thus with the increase in methyl group, hydrogen bonding and stabilisation by solvation decreases. The net effect is when we move from secondary to tertiary amine basic strength actually decreases.
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संबंधित प्रश्न
Arrange the following:
In increasing order of boiling point:
C2H5OH, (CH3)2NH, C2H5NH2
Complete the following reaction:
\[\ce{C6H5N2Cl + H3PO2 + H2O ->}\]
Give reasons CH3NH2 is more basic than C6H5NH2.
Illustrate the following reactions giving suitable example in each case
Ammonolysis
Arrange the following in increasing order of basic strength :
C6H5NH2, C6H5NHCH3, C6H5N(CH3)2
Which of the following have less melting point than amine?
Which of the following amines form maximum hydrogen bonds within themselves?
Arrange the following in increasing order of their boiling point:
C2H5OH, C2H5NH2, (C2H5)3N
Write short note on the following:
Ammonolysis
The correct order of decreasing basic strength of the given amines is:
