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प्रश्न
Complete the following acid-base reaction and name the product:
\[\ce{CH3CH2CH2NH2 + HCl ->}\]
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उत्तर
\[\ce{\underset{n-Propylamine}{CH3CH2CH2NH2} + HCl -> \underset{n-Propylammonium chloride}{CH3CH2CH2\overset{+}{N}H3Cl-}}\]
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संबंधित प्रश्न
Give reasons for the following: (CH3)2NH is more basic than (CH3)3N in an aqueous solution.
Give reason for the following:
Primary amines have higher boiling point than tertiary amines.
Arrange the following: C2H5NH2, C2H5OH, (CH3)3N – in the increasing order of their boiling point
Arrange the following in increasing order of their basic strength :
C6H5 – NH2, C6H5 – CH2 – NH2, C6H5 – NH – CH3
Arrange the following in increasing order of their basic strength:
CH3NH2, (CH3)2NH, (CH3)3N, C6H5NH2, C6H5CH2NH2
Arrange the following:
In increasing order of boiling point:
C2H5OH, (CH3)2NH, C2H5NH2
Accomplish the following conversion:
Aniline to p-bromoaniline
Give a plausible explanation for the following:
Why are aliphatic amines stronger bases than aromatic amines?
Complete the following reaction:
\[\ce{C6H5N2Cl + H3PO2 + H2O ->}\]
Give reasons CH3NH2 is more basic than C6H5NH2.
Arrange the following in the increasing order of their pKb values:
C6H5NH2, C2H5NH2, C6H5NHCH3
Illustrate the following reactions giving suitable example in each case
Ammonolysis
Arrange the following in increasing order of basic strength :
C6H5NH2, C6H5NHCH3, C6H5N(CH3)2
The CORRECT decreasing order of solubility in water will be ____________.
Which of the following should be most volatile?
A compound Z with molecular formula \[\ce{C3H9N}\] reacts with \[\ce{C6H5SO2Cl}\] to give a solid, insoluble in alkali. Identify Z.
Acetic acid exist as dimer in benzene due to
Dimerisation of carboxylic acids is due to
Arrange the decreasing boiling point.
\[\ce{CH3COOH, C2H5OH, CH3NH2, CH3OCH3}\]
