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Abcd is a Trapezium in Which Ab || Dc. If Ar (δAbd) = 24 Cm2 and Ab = 8 Cm, Then Height of δAbc is - Mathematics

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Question

ABCD is a trapezium in which AB || DC. If ar (ΔABD) = 24 cm2 and AB = 8 cm, then height of ΔABC is

Options

  •  3 cm

  • 4 cm

  •  6 cm

  •  8 cm

MCQ
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Solution

Given: (1) ABCD is a trapezium, with parallel sides AB and DC

(2) Area of ΔADB = 24 cm2

(3) AB = 8 cm

To find: Height of ΔABC.

Calculation: We know that ,” two triangles with the same base and between the same parallels are equal in area.”

Here we can see that, ΔADB and ΔACB are on the same base AB.

Hence,

Area of ΔACB = Area of ΔADB

Area of ΔACB = 24

`1/2 (8 xx h) =24 `

                `h = (24 xx 2)/8`

                h = 6 cm 

 

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Chapter 14: Areas of Parallelograms and Triangles - Exercise 14.5 [Page 61]

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RD Sharma Mathematics [English] Class 9
Chapter 14 Areas of Parallelograms and Triangles
Exercise 14.5 | Q 16 | Page 61

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