Advertisements
Advertisements
प्रश्न
ABCD is a trapezium in which AB || DC. If ar (ΔABD) = 24 cm2 and AB = 8 cm, then height of ΔABC is
विकल्प
3 cm
4 cm
6 cm
8 cm
Advertisements
उत्तर
Given: (1) ABCD is a trapezium, with parallel sides AB and DC
(2) Area of ΔADB = 24 cm2
(3) AB = 8 cm
To find: Height of ΔABC.
Calculation: We know that ,” two triangles with the same base and between the same parallels are equal in area.”

Here we can see that, ΔADB and ΔACB are on the same base AB.
Hence,
Area of ΔACB = Area of ΔADB
Area of ΔACB = 24
`1/2 (8 xx h) =24 `
`h = (24 xx 2)/8`
h = 6 cm
APPEARS IN
संबंधित प्रश्न
A point D is taken on the side BC of a ΔABC such that BD = 2DC. Prove that ar(Δ ABD) =
2ar (ΔADC).
In below fig., PSDA is a parallelogram in which PQ = QR = RS and AP || BQ || CR. Prove
that ar (Δ PQE) = ar (ΔCFD).

PQRS is a rectangle inscribed in a quadrant of a circle of radius 13 cm. A is any point on PQ. If PS = 5 cm, then find ar (ΔRAS)
In a ΔABC, D, E, F are the mid-points of sides BC, CA and AB respectively. If ar (ΔABC) = 16cm2, then ar (trapezium FBCE) =
The medians of a triangle ABC intersect each other at point G. If one of its medians is AD,
prove that:
(i) Area ( ΔABD ) = 3 x Area ( ΔBGD )
(ii) Area ( ΔACD ) = 3 x Area ( ΔCGD )
(iii) Area ( ΔBGC ) = `1/3` x Area ( ΔABC ).
A floor is 40 m long and 15 m broad. It is covered with tiles, each measuring 60 cm by 50 cm. Find the number of tiles required to cover the floor.
Length of a rectangle is 30 m and its breadth is 20 m. Find the increase in its area if its length is increased by 10 m and its breadth is doubled.
The side of a square field is 16 m. What will be increase in its area, if each of its sides is doubled?
Which has the smaller area - two five-rupee notes together or a hundred rupee notes?
Altogether how many squares can be arranged on it?
