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Abc is a Triangle and Through A, B, C Lines Are Drawn Parallel to Bc, Ca and Ab Respectively Intersecting at P, Q and R. Prove that the Perimeter of δPqr is Double the Perimeter of δAbc - Mathematics

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Question

ABC is a triangle and through A, B, C lines are drawn parallel to BC, CA and AB respectively
intersecting at P, Q and R. Prove that the perimeter of ΔPQR is double the perimeter of
ΔABC

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Solution

Clearly ABCQ and ARBC are parallelograms.

∴ BC = AQ and BC = AR

⇒ AQ = AR

⇒ A is the midpoint of QR .

Similarly B and C are the midpoints of PR and PQ respectively

∴ AB = `1/2` PQ, BC = `1/2` QR, CA = `1/2 `PR

⇒ PQ = 2AB,QR = 2BC and PR = 2CA

⇒ PQ + QR + RP = 2( AB + BC + CA)

⇒ Perimeter of DPQR = 2   [Perimeter of DABC ]

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Chapter 13: Quadrilaterals - Exercise 13.4 [Page 64]

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RD Sharma Mathematics [English] Class 9
Chapter 13 Quadrilaterals
Exercise 13.4 | Q 14 | Page 64

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