English

Aafd∫-aaf(x)dx = 0 if f is an ______ function.

Advertisements
Advertisements

Question

`int_(-"a")^"a" "f"(x) "d"x` = 0 if f is an ______ function.

Fill in the Blanks
Advertisements

Solution

`int_(-"a")^"a" "f"(x) "d"x` = 0 if f is an Odd function.

shaalaa.com
  Is there an error in this question or solution?
Chapter 7: Integrals - Solved Examples [Page 163]

APPEARS IN

NCERT Exemplar Mathematics Exemplar [English] Class 12
Chapter 7 Integrals
Solved Examples | Q 30 | Page 163

RELATED QUESTIONS

If `int_0^alpha(3x^2+2x+1)dx=14` then `alpha=`

(A) 1

(B) 2

(C) –1

(D) –2


By using the properties of the definite integral, evaluate the integral:

`int_0^(pi/2)  sqrt(sinx)/(sqrt(sinx) + sqrt(cos x)) dx` 


By using the properties of the definite integral, evaluate the integral:

`int_0^(pi/2) (sin x - cos x)/(1+sinx cos x) dx`


By using the properties of the definite integral, evaluate the integral:

`int_0^pi log(1+ cos x) dx`


`int_(-pi/2)^(pi/2) (x^3 + x cos x + tan^5 x + 1) dx ` is ______.


The value of `int_0^(pi/2) log  ((4+ 3sinx)/(4+3cosx))` dx is ______.


Prove that `int_0^af(x)dx=int_0^af(a-x) dx`

hence evaluate `int_0^(pi/2)sinx/(sinx+cosx) dx`


\[\int\limits_0^k \frac{1}{2 + 8 x^2} dx = \frac{\pi}{16},\] find the value of k.


\[\int_\pi^\frac{3\pi}{2} \sqrt{1 - \cos2x}dx\]

Evaluate : \[\int(3x - 2) \sqrt{x^2 + x + 1}dx\] .


Evaluate : `int _0^(pi/2) "sin"^ 2  "x"  "dx"`


`int_0^1 "e"^(2x) "d"x` = ______


`int_0^(pi/4) (sec^2 x)/((1 + tan x)(2 + tan x))`dx = ?


The c.d.f, F(x) associated with p.d.f. f(x) = 3(1- 2x2). If 0 < x < 1 is k`(x - (2x^3)/"k")`, then value of k is ______.


`int_0^1 (1 - x/(1!) + x^2/(2!) - x^3/(3!) + ... "upto" ∞)` e2x dx = ?


`int_0^{pi/2} xsinx dx` = ______


`int_"a"^"b" sqrtx/(sqrtx + sqrt("a" + "b" - x)) "dx"` = ______.


If f(x) = |x - 2|, then `int_-2^3 f(x) dx` is ______


`int_{pi/6}^{pi/3} sin^2x dx` = ______ 


`int_0^{1/sqrt2} (sin^-1x)/(1 - x^2)^{3/2} dx` = ______ 


`int_0^{pi/2} (cos2x)/(cosx + sinx)dx` = ______


`int_(-1)^1 (x + x^3)/(9 - x^2)  "d"x` = ______.


Evaluate `int_0^(pi/2) (tan^7x)/(cot^7x + tan^7x) "d"x`


Find `int_2^8 sqrt(10 - x)/(sqrt(x) + sqrt(10 - x)) "d"x`


If `int_0^"a" 1/(1 + 4x^2) "d"x = pi/8`, then a = ______.


`int_0^(2"a") "f"("x") "dx" = int_0^"a" "f"("x") "dx" + int_0^"a" "f"("k" - "x") "dx"`, then the value of k is:


Evaluate: `int_((-π)/2)^(π/2) (sin|x| + cos|x|)dx`


If `intxf(x)dx = (f(x))/2` then f(x) = ex.


`int_0^π(xsinx)/(1 + cos^2x)dx` equals ______.


If `int_0^K dx/(2 + 18x^2) = π/24`, then the value of K is ______.


Evaluate: `int_(-π//4)^(π//4) (cos 2x)/(1 + cos 2x)dx`.


Evaluate the following integral:

`int_0^1 x(1-x)^5 dx`


`int_0^(2a)f(x)/(f(x)+f(2a-x))  dx` = ______


Evaluate the following integrals:

`int_-9^9 x^3/(4 - x^3 ) dx`


Evaluate the following integral:

`int_-9^9 x^3/(4-x^2)dx`


Evaluate the following integral:

`int_0^1 x (1 - x)^5 dx`


Solve the following.

`int_0^1e^(x^2)x^3dx`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×