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Aafd∫-aaf(x)dx = 0 if f is an ______ function. - Mathematics

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प्रश्न

`int_(-"a")^"a" "f"(x) "d"x` = 0 if f is an ______ function.

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उत्तर

`int_(-"a")^"a" "f"(x) "d"x` = 0 if f is an Odd function.

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अध्याय 7: Integrals - Solved Examples [पृष्ठ १६३]

APPEARS IN

एनसीईआरटी एक्झांप्लर Mathematics [English] Class 12
अध्याय 7 Integrals
Solved Examples | Q 30 | पृष्ठ १६३

संबंधित प्रश्न

By using the properties of the definite integral, evaluate the integral:

`int_0^(pi/2)  sqrt(sinx)/(sqrt(sinx) + sqrt(cos x)) dx` 


By using the properties of the definite integral, evaluate the integral:

`int_(-5)^5 | x + 2| dx`


By using the properties of the definite integral, evaluate the integral:

`int_0^(pi/4) log (1+ tan x) dx`


By using the properties of the definite integral, evaluate the integral:

`int_0^pi (x  dx)/(1+ sin x)`


By using the properties of the definite integral, evaluate the integral:

`int_0^4 |x - 1| dx`


The value of `int_0^(pi/2) log  ((4+ 3sinx)/(4+3cosx))` dx is ______.


If \[f\left( a + b - x \right) = f\left( x \right)\] , then prove that

\[\int_a^b xf\left( x \right)dx = \left( \frac{a + b}{2} \right) \int_a^b f\left( x \right)dx\]

Evaluate  : `int "x"^2/("x"^4 + 5"x"^2 + 6) "dx"`


Prove that `int_0^"a" "f" ("x") "dx" = int_0^"a" "f" ("a" - "x") "d x",` hence evaluate `int_0^pi ("x" sin "x")/(1 + cos^2 "x") "dx"`


Evaluate the following integrals : `int_2^5 sqrt(x)/(sqrt(x) + sqrt(7 - x))*dx`


Choose the correct alternative:

`int_(-9)^9 x^3/(4 - x^2)  "d"x` =


Evaluate `int_0^1 x(1 - x)^5  "d"x`


By completing the following activity, Evaluate `int_2^5 (sqrt(x))/(sqrt(x) + sqrt(7 - x))  "d"x`.

Solution: Let I = `int_2^5 (sqrt(x))/(sqrt(x) + sqrt(7 - x))  "d"x`     ......(i)

Using the property, `int_"a"^"b" "f"(x) "d"x = int_"a"^"b" "f"("a" + "b" - x)  "d"x`, we get

I = `int_2^5 ("(  )")/(sqrt(7 - x) + "(  )")  "d"x`   ......(ii)

Adding equations (i) and (ii), we get

2I = `int_2^5 (sqrt(x))/(sqrt(x) - sqrt(7 - x))  "d"x + (   )  "d"x`

2I = `int_2^5 (("(    )" + "(     )")/("(    )" + "(     )"))  "d"x`

2I = `square`

∴ I =  `square`


`int_0^{pi/4} (sin2x)/(sin^4x + cos^4x)dx` = ____________


`int_0^{pi/4} (sin2x)/(sin^4x + cos^4x)dx` = ____________


`int_0^1 x tan^-1x  dx` = ______ 


The value of `int_1^3 dx/(x(1 + x^2))` is ______ 


If `int_0^"k" "dx"/(2 + 32x^2) = pi/32,` then the value of k is ______.


`int_0^pi sin^2x.cos^2x  dx` = ______ 


`int_(pi/4)^(pi/2) sqrt(1-sin 2x)  dx =` ______.


Which of the following is true?


`int_0^1 "e"^(5logx) "d"x` = ______.


Evaluate `int_0^(pi/2) (tan^7x)/(cot^7x + tan^7x) "d"x`


`int_(-1)^1 (x^3 + |x| + 1)/(x^2 + 2|x| + 1) "d"x` is equal to ______.


`int_((-pi)/4)^(pi/4) "dx"/(1 + cos2x)` is equal to ______.


Evaluate:

`int_2^8 (sqrt(10 - "x"))/(sqrt"x" + sqrt(10 - "x")) "dx"`


`int_(-5)^5  x^7/(x^4 + 10)  dx` = ______.


Evaluate: `int_(pi/6)^(pi/3) (dx)/(1 + sqrt(tanx)`


If `int_a^b x^3 dx` = 0, then `(x^4/square)_a^b` = 0

⇒ `1/4 (square - square)` = 0

⇒ b4 – `square` = 0

⇒ (b2 – a2)(`square` + `square`) = 0

⇒ b2 – `square` = 0 as a2 + b2 ≠ 0

⇒ b = ± `square`


If `int_0^K dx/(2 + 18x^2) = π/24`, then the value of K is ______.


Evaluate `int_-1^1 |x^4 - x|dx`.


For any integer n, the value of `int_-π^π e^(cos^2x) sin^3 (2n + 1)x  dx` is ______.


Evaluate: `int_0^(π/4) log(1 + tanx)dx`.


Evaluate the following limit :

`lim_("x"->3)[sqrt("x"+6)/"x"]`


Evaluate the following integral:

`int_-9^9 x^3/(4-x^2)dx`


Evaluate the following integral:

`int_0^1 x (1 - x)^5 dx`


Evaluate the following integral:

`int_0^1x(1-x)^5dx`


Evaluate the following integral:

`int_-9^9x^3/(4-x^2)dx`


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