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Aafd∫-aaf(x)dx = 0 if f is an ______ function.

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प्रश्न

`int_(-"a")^"a" "f"(x) "d"x` = 0 if f is an ______ function.

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उत्तर

`int_(-"a")^"a" "f"(x) "d"x` = 0 if f is an Odd function.

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अध्याय 7: Integrals - Solved Examples [पृष्ठ १६३]

APPEARS IN

एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 12
अध्याय 7 Integrals
Solved Examples | Q 30 | पृष्ठ १६३

संबंधित प्रश्न

Evaluate :`int_0^pi(xsinx)/(1+sinx)dx`


By using the properties of the definite integral, evaluate the integral:

`int_0^(pi/2)  sqrt(sinx)/(sqrt(sinx) + sqrt(cos x)) dx` 


By using the properties of the definite integral, evaluate the integral:

`int_0^a  sqrtx/(sqrtx + sqrt(a-x))   dx`


By using the properties of the definite integral, evaluate the integral:

`int_0^4 |x - 1| dx`


Evaluate the definite integrals `int_0^pi (x tan x)/(sec x + tan x)dx`


\[\int_\pi^\frac{3\pi}{2} \sqrt{1 - \cos2x}dx\]

Evaluate : `int _0^(pi/2) "sin"^ 2  "x"  "dx"`


Evaluate : `int 1/("x" [("log x")^2 + 4])  "dx"`


Prove that `int_0^"a" "f" ("x") "dx" = int_0^"a" "f" ("a" - "x") "d x",` hence evaluate `int_0^pi ("x" sin "x")/(1 + cos^2 "x") "dx"`


Find : `int_  (2"x"+1)/(("x"^2+1)("x"^2+4))d"x"`.


Evaluate the following integrals : `int_2^5 sqrt(x)/(sqrt(x) + sqrt(7 - x))*dx`


By completing the following activity, Evaluate `int_2^5 (sqrt(x))/(sqrt(x) + sqrt(7 - x))  "d"x`.

Solution: Let I = `int_2^5 (sqrt(x))/(sqrt(x) + sqrt(7 - x))  "d"x`     ......(i)

Using the property, `int_"a"^"b" "f"(x) "d"x = int_"a"^"b" "f"("a" + "b" - x)  "d"x`, we get

I = `int_2^5 ("(  )")/(sqrt(7 - x) + "(  )")  "d"x`   ......(ii)

Adding equations (i) and (ii), we get

2I = `int_2^5 (sqrt(x))/(sqrt(x) - sqrt(7 - x))  "d"x + (   )  "d"x`

2I = `int_2^5 (("(    )" + "(     )")/("(    )" + "(     )"))  "d"x`

2I = `square`

∴ I =  `square`


`int_0^(pi"/"4)` log(1 + tanθ) dθ = ______


`int_0^{pi/2}((3sqrtsecx)/(3sqrtsecx + 3sqrt(cosecx)))dx` = ______ 


`int_-9^9 x^3/(4 - x^2)` dx = ______


If `int_0^"a" sqrt("a - x"/x) "dx" = "K"/2`, then K = ______.


f(x) =  `{:{(x^3/k;       0 ≤ x ≤ 2), (0;     "otherwise"):}` is a p.d.f. of X. The value of k is ______


If f(x) = |x - 2|, then `int_-2^3 f(x) dx` is ______


`int_(-1)^1 log ((2 - x)/(2 + x)) "dx" = ?`


The value of `int_2^7 (sqrtx)/(sqrt(9 - x) + sqrtx)dx` is ______ 


Find `int_2^8 sqrt(10 - x)/(sqrt(x) + sqrt(10 - x)) "d"x`


`int_0^(2"a") "f"(x) "d"x = 2int_0^"a" "f"(x) "d"x`, if f(2a – x) = ______.


Evaluate:

`int_2^8 (sqrt(10 - "x"))/(sqrt"x" + sqrt(10 - "x")) "dx"`


Evaluate: `int_0^(π/2) 1/(1 + (tanx)^(2/3)) dx`


Evaluate: `int_1^3 sqrt(x)/(sqrt(x) + sqrt(4) - x) dx`


`int_a^b f(x)dx` = ______.


`int_a^b f(x)dx = int_a^b f(x - a - b)dx`.


If `intxf(x)dx = (f(x))/2` then f(x) = ex.


If `int_(-a)^a(|x| + |x - 2|)dx` = 22, (a > 2) and [x] denotes the greatest integer ≤ x, then `int_a^(-a)(x + [x])dx` is equal to ______.


If `β + 2int_0^1x^2e^(-x^2)dx = int_0^1e^(-x^2)dx`, then the value of β is ______.


Let `int ((x^6 - 4)dx)/((x^6 + 2)^(1/4).x^4) = (ℓ(x^6 + 2)^m)/x^n + C`, then `n/(ℓm)` is equal to ______.


What is `int_0^(π/2)` sin 2x ℓ n (cot x) dx equal to ?


`int_0^(π/4) x. sec^2 x  dx` = ______.


Evaluate the following integral:

`int_0^1 x(1 - 5)^5`dx


Evaluate the following integral:

`int_-9^9 x^3 / (4 - x^2) dx`


Evaluate the following integral:

`int_0^1x(1-x)^5dx`


Solve the following.

`int_0^1e^(x^2)x^3dx`


`int_(pi"/"11)^(9pi"/"22) (dx)/(1 + sqrttan x)` =


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