हिंदी

By using the properties of the definite integral, evaluate the integral: ∫04|x-1|dx

Advertisements
Advertisements

प्रश्न

By using the properties of the definite integral, evaluate the integral:

`int_0^4 |x - 1| dx`

योग
Advertisements

उत्तर

`int_0^4  abs (x - 1)  dx`

Define,

`abs(x - 1) = {(-(x-1), if x-1<0, or x < 1),(x-1, if x - 1>=0, or x>=1):}`

`int_0^1 abs (x - 1)  dx + int_1^4  abs(x - 1)  dx`

`int_0^1 - (x - 1)  "dx" + int_1^4  (x - 1) dx`

`= - [x^2/2 - x]_0^1 + [x^2/2 - x]_1^4`

`= [(1/2 - 1) - 0] + (16/2 - 4) - (1/2 - 1)`

`= 1/2 + 4 + 1/2`

`= (1 + 8 + 1)/2`

= 5

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Integrals - Exercise 7.11 [पृष्ठ ३४७]

APPEARS IN

एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 7 Integrals
Exercise 7.11 | Q 18 | पृष्ठ ३४७

संबंधित प्रश्न

Evaluate : `int e^x[(sqrt(1-x^2)sin^-1x+1)/(sqrt(1-x^2))]dx`


By using the properties of the definite integral, evaluate the integral:

`int_0^(pi/2) cos^2 x dx`


By using the properties of the definite integral, evaluate the integral:

`int_0^(pi/2) sin^(3/2)x/(sin^(3/2)x + cos^(3/2) x) dx`


By using the properties of the definite integral, evaluate the integral:

`int_(-5)^5 | x + 2| dx`


By using the properties of the definite integral, evaluate the integral:

`int_2^8 |x - 5| dx`


By using the properties of the definite integral, evaluate the integral:

`int_0^pi (x  dx)/(1+ sin x)`


By using the properties of the definite integral, evaluate the integral:

`int_0^(2x) cos^5 xdx`


By using the properties of the definite integral, evaluate the integral:

`int_0^(pi/2) (sin x - cos x)/(1+sinx cos x) dx`


\[\int\limits_0^a 3 x^2 dx = 8,\] find the value of a.


If \[f\left( a + b - x \right) = f\left( x \right)\] , then prove that

\[\int_a^b xf\left( x \right)dx = \left( \frac{a + b}{2} \right) \int_a^b f\left( x \right)dx\]

Evaluate : `int  "e"^(3"x")/("e"^(3"x") + 1)` dx


Evaluate :  ∫ log (1 + x2) dx


`int_0^{pi/4} (sin2x)/(sin^4x + cos^4x)dx` = ____________


`int_0^{pi/2} cos^2x  dx` = ______ 


If f(x) = |x - 2|, then `int_-2^3 f(x) dx` is ______


`int_{pi/6}^{pi/3} sin^2x dx` = ______ 


If `int_0^"k" "dx"/(2 + 32x^2) = pi/32,` then the value of k is ______.


The value of `int_2^7 (sqrtx)/(sqrt(9 - x) + sqrtx)dx` is ______ 


Find `int_0^(pi/4) sqrt(1 + sin 2x) "d"x`


`int_((-pi)/4)^(pi/4) "dx"/(1 + cos2x)` is equal to ______.


`int_0^(pi/2) sqrt(1 - sin2x)  "d"x` is equal to ______.


If `int (log "x")^2/"x" "dx" = (log "x")^"k"/"k" + "c"`, then the value of k is:


Evaluate: `int_(-1)^3 |x^3 - x|dx`


`int_0^1 1/(2x + 5) dx` = ______.


`int_4^9 1/sqrt(x)dx` = ______.


`int_0^π(xsinx)/(1 + cos^2x)dx` equals ______.


The value of the integral `int_0^1 x cot^-1(1 - x^2 + x^4)dx` is ______.


`int_(π/3)^(π/2) x sin(π[x] - x)dx` is equal to ______.


Evaluate `int_-1^1 |x^4 - x|dx`.


Evaluate the following integral:

`int_0^1 x(1 - 5)^5`dx


Evaluate the following integral:

`int_0^1x (1 - x)^5 dx`


Evaluate the following integral:

`int_-9^9 x^3/(4 - x^2) dx`


Solve the following.

`int_0^1 e^(x^2) x^3dx`


Evaluate the following integral:

`int_0^1 x(1-x)^5 dx`


Evaluate:

`int_0^6 |x + 3|dx`


Solve the following.

`int_0^1e^(x^2)x^3dx`


The value of \[\int_{-1}^{1}\left(\sqrt{1+x+x^{2}}-\sqrt{1-x+x^{2}}\right)\mathrm{d}x\] is


What is the value of \[\int_{-\frac{\pi}{4}}^{\frac{\pi}{4}}\sin^{2}x\,dx\]?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×