हिंदी

By using the properties of the definite integral, evaluate the integral: ∫0a xx +a-x dx - Mathematics

Advertisements
Advertisements

प्रश्न

By using the properties of the definite integral, evaluate the integral:

`int_0^a  sqrtx/(sqrtx + sqrt(a-x))   dx`

योग
Advertisements

उत्तर

Let I = `int_0^a  (sqrtx)/(sqrtx + sqrt(a - x))  dx`       ....(i)

`= I = int_0^a (sqrt(a - x))/(sqrt(a - x) + sqrt (a - (a - x)))`

I = `int_0^a sqrt(a - x)/(sqrt(a - x) + sqrtx)  dx`        ....(ii)

`[because int_0^a f(x) dx = int_0^a f(a - x)  dx]`

On adding equation (i) and (ii),

2 I = `int_0^a  (sqrtx + sqrt(a - x))/(sqrt(a - x) + sqrtx)  dx`

2 I `= int_0^a 1 * dx => [x]_0^a`

⇒ 2I = a

∴ `I = a/2`

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Integrals - Exercise 7.11 [पृष्ठ ३४७]

APPEARS IN

एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 7 Integrals
Exercise 7.11 | Q 17 | पृष्ठ ३४७

संबंधित प्रश्न

Evaluate: `int_(-a)^asqrt((a-x)/(a+x)) dx`


By using the properties of the definite integral, evaluate the integral:

`int_0^(pi/2)  (cos^5  xdx)/(sin^5 x + cos^5 x)`


By using the properties of the definite integral, evaluate the integral:

`int_0^(2x) cos^5 xdx`


Show that `int_0^a f(x)g (x)dx = 2 int_0^a f(x) dx`  if f and g are defined as f(x) = f(a-x) and g(x) + g(a-x) = 4.


Evaluate : `int _0^(pi/2) "sin"^ 2  "x"  "dx"`


Prove that `int_0^"a" "f" ("x") "dx" = int_0^"a" "f" ("a" - "x") "d x",` hence evaluate `int_0^pi ("x" sin "x")/(1 + cos^2 "x") "dx"`


Evaluate the following integrals : `int_2^5 sqrt(x)/(sqrt(x) + sqrt(7 - x))*dx`


`int_0^2 e^x dx` = ______.


`int_1^2 1/(2x + 3)  dx` = ______


`int_2^4 x/(x^2 + 1)  "d"x` = ______


Evaluate `int_1^3 x^2*log x  "d"x`


`int_0^4 1/(1 + sqrtx)`dx = ______.


`int_"a"^"b" sqrtx/(sqrtx + sqrt("a" + "b" - x)) "dx"` = ______.


f(x) =  `{:{(x^3/k;       0 ≤ x ≤ 2), (0;     "otherwise"):}` is a p.d.f. of X. The value of k is ______


`int_0^1 x tan^-1x  dx` = ______ 


`int_-1^1x^2/(1+x^2)  dx=` ______.


`int_(-pi/4)^(pi/4) 1/(1 - sinx) "d"x` = ______.


`int_0^1 "e"^(5logx) "d"x` = ______.


`int_("a" + "c")^("b" + "c") "f"(x) "d"x` is equal to ______.


`int_0^(2"a") "f"("x") "dx" = int_0^"a" "f"("x") "dx" + int_0^"a" "f"("k" - "x") "dx"`, then the value of k is:


Evaluate: `int_(pi/6)^(pi/3) (dx)/(1 + sqrt(tanx)`


Let a be a positive real number such that `int_0^ae^(x-[x])dx` = 10e – 9 where [x] is the greatest integer less than or equal to x. Then, a is equal to ______.


If `β + 2int_0^1x^2e^(-x^2)dx = int_0^1e^(-x^2)dx`, then the value of β is ______.


The value of the integral `int_0^sqrt(2)([sqrt(2 - x^2)] + 2x)dx` (where [.] denotes greatest integer function) is ______.


Let `int_0^∞ (t^4dt)/(1 + t^2)^6 = (3π)/(64k)` then k is equal to ______.


Let f be continuous periodic function with period 3, such that `int_0^3f(x)dx` = 1. Then the value of `int_-4^8f(2x)dx` is ______.


If `lim_("n"→∞)(int_(1/("n"+1))^(1/"n") tan^-1("n"x)"d"x)/(int_(1/("n"+1))^(1/"n") sin^-1("n"x)"d"x) = "p"/"q"`, (where p and q are coprime), then (p + q) is ______.


Evaluate: `int_0^π x/(1 + sinx)dx`.


`int_0^(2a)f(x)/(f(x)+f(2a-x))  dx` = ______


Evaluate the following integral:

`int_0^1x (1 - x)^5 dx`


Evaluate: `int_-1^1 x^17.cos^4x  dx`


Evaluate:

`int_0^1 |2x + 1|dx`


Evaluate the following integral:

`int_-9^9 x^3 / (4 - x^2) dx`


Evaluate the following integral:

`int_-9^9x^3/(4-x^2)dx`


Solve the following.

`int_0^1e^(x^2)x^3dx`


Evaluate the following definite intergral:

`int_1^2 (3x)/(9x^2 - 1) dx`


Evaluate the following integral:

`int_0^1x(1 - x)^5dx`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×