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Evaluate: ∫-13|x3-x|dx - Mathematics

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प्रश्न

Evaluate: `int_(-1)^3 |x^3 - x|dx`

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उत्तर

Let I = `int_(-1)^2|x^3 - x|dx`

= `int_(-1)^2|x(x^2 - 1)|dx`

= `int_(-1)^2|x(x - 1)(x + 1)|dx`

Here, x3 – x = 0, when x = 0, 1, –1

Value of x Value of (x3 – x)
–1 < x < 0 +ve
0 < x < 1 –ve
1 < x < 2 +ve

∴ |x3 – x| = `{{:(x^3 - x, if  -1 < x < 0 and 1 < x < 2),(-x^3 + x, if 0 < x < 1):}`

I = `int_(-1)^0(x^3 - x)dx + int_1^1(-x^3 + x)dx + int_1^2(x^3 - x)dx`

= `[x^4/4 - x^2/2]_-1^0 + [(-x^4)/4 + x^2/2]_0^1 + [x^4/4 - x^2/2]_1^2`

= `1/4 + 1/4 + 2 + 1/4`

= `2 + 3/4`

= `11/4`

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2021-2022 (March) Term 2 - Outside Delhi Set 2

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