मराठी

By using the properties of the definite integral, evaluate the integral: ∫04|x-1|dx

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प्रश्न

By using the properties of the definite integral, evaluate the integral:

`int_0^4 |x - 1| dx`

बेरीज
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उत्तर

`int_0^4  abs (x - 1)  dx`

Define,

`abs(x - 1) = {(-(x-1), if x-1<0, or x < 1),(x-1, if x - 1>=0, or x>=1):}`

`int_0^1 abs (x - 1)  dx + int_1^4  abs(x - 1)  dx`

`int_0^1 - (x - 1)  "dx" + int_1^4  (x - 1) dx`

`= - [x^2/2 - x]_0^1 + [x^2/2 - x]_1^4`

`= [(1/2 - 1) - 0] + (16/2 - 4) - (1/2 - 1)`

`= 1/2 + 4 + 1/2`

`= (1 + 8 + 1)/2`

= 5

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पाठ 7: Integrals - Exercise 7.11 [पृष्ठ ३४७]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
पाठ 7 Integrals
Exercise 7.11 | Q 18 | पृष्ठ ३४७

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