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Question
A solid weighs 1.5 kgf in air and 0.9 kgf in a liquid of density 1.2 × 103 kg m-3. Calculate R. D. of solid.
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Solution
Weight of body in air , W1 = 1.5 kgf
Weight of body when completely immersed in liquid W2 = 0.9 kgf
Density of liquid = 1.2 × 103 kgm-3
R.D. of liquid = 1.2
R.D. of body = `"W"_1/("W"_1 - "W"_2) xx "R.D. of liquid"`
R.D. of body = `1.5/(1.5 - 0.9) xx 1.2`
R.D. of body = `1.5/0.6 xx 1.2`
R.D. of body = 3
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