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Question
A body weighs W1gf in air and when immersed in a liquid it weighs W2gf, while it weights W3gf on immersing it in water. Find:
- volume of the body
- upthrust due to liquid
- relative density of the solid
- relative density of the liquid
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Solution
(i) Volume of the body = W1 − W3 cm3
(ii) Upthrust due to liquid = loss in weight when immersed in liquid = W1 − W2 gf
(iii)
Weight of a body in air = W1gf
Weight of that body in liquid = W2gf
Weight of that body in water = W3gf
RD of solid = `"Weight of solid in air"/"Weight in air - Weight in water"`
= `"W"_1/("W"_1 - "W"_3)`
(iv)
Weight of a body in air = W1gf
Weight of that body in liquid = W2gf
Weight of that body in water = W3gf
RD of Liquid = `(W_1 - W_2)/(W_1 - W_3)`
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