Advertisements
Advertisements
प्रश्न
A body weighs W1gf in air and when immersed in a liquid it weighs W2gf, while it weights W3gf on immersing it in water. Find:
- volume of the body
- upthrust due to liquid
- relative density of the solid
- relative density of the liquid
Advertisements
उत्तर
(i) Volume of the body = W1 − W3 cm3
(ii) Upthrust due to liquid = loss in weight when immersed in liquid = W1 − W2 gf
(iii)
Weight of a body in air = W1gf
Weight of that body in liquid = W2gf
Weight of that body in water = W3gf
RD of solid = `"Weight of solid in air"/"Weight in air - Weight in water"`
= `"W"_1/("W"_1 - "W"_3)`
(iv)
Weight of a body in air = W1gf
Weight of that body in liquid = W2gf
Weight of that body in water = W3gf
RD of Liquid = `(W_1 - W_2)/(W_1 - W_3)`
APPEARS IN
संबंधित प्रश्न
A sphere of iron and another sphere of wood of the same radius are held under water. Compare the upthrust on the two spheres.
[Hint: Both have equal volume inside the water].
How does the density of material of a body determine whether it will float or sink in water?
What is the unit of relative density?
A solid weighs 120 gf in air and and 105 gf when it is completely immersed in water. Calculate the relative density of solid.
A piece of stone of mass 113 g sinks to the bottom in water contained in a measuring cylinder and water level in cylinder rises from 30 ml to 40 ml. Calculate R.D. of stone.
A cylinder made of copper and aluminium floats in mercury of density 13.6 gem-3, such that 0.26th part of it is below mercury. Find the density of solid.
An iceberg floats in sea water of density 1.17 g cm 3, such that 2/9 of its volume is above sea water. Find the density of iceberg.
A piece of wax floats in brine. What fraction of its volume will be immersed?
R.D. of wax = 0.95, R.D. of brine = 1.1.
Calculate the mass of a body whose volume is 2m3 and relative density is 0.52.
