Advertisements
Advertisements
प्रश्न
A body weighs W1gf in air and when immersed in a liquid it weighs W2gf, while it weights W3gf on immersing it in water. Find:
- volume of the body
- upthrust due to liquid
- relative density of the solid
- relative density of the liquid
Advertisements
उत्तर
(i) Volume of the body = W1 − W3 cm3
(ii) Upthrust due to liquid = loss in weight when immersed in liquid = W1 − W2 gf
(iii)
Weight of a body in air = W1gf
Weight of that body in liquid = W2gf
Weight of that body in water = W3gf
RD of solid = `"Weight of solid in air"/"Weight in air - Weight in water"`
= `"W"_1/("W"_1 - "W"_3)`
(iv)
Weight of a body in air = W1gf
Weight of that body in liquid = W2gf
Weight of that body in water = W3gf
RD of Liquid = `(W_1 - W_2)/(W_1 - W_3)`
APPEARS IN
संबंधित प्रश्न
How does the density of material of a body determine whether it will float or sink in water?
How are the (i) Mass, (ii) Volume and (iii) Density of a metallic piece affected, if at all, with an increase in temperature?
Differentiate between density and relative density of a substance.
A body weighs 20 gf in air and 18.0 gf in water. Calculate the relative density of the material of the body.
A solid of density 7600 kgm3 is found to weigh 0.950 kgf in air. If 4/5 volume of solid is completely immersed in a solution of density 900 kgm3, find the apparent weight of solid in a liquid.
A glass cylinder of length 12 x 10-2 m and area of crosssection 5 x 10-4 m2 has a density of 2500 kgm-3. It is immersed in a liquid of density 1500 kgm-3, such that 3/8. of its length is above the liquid. Find the apparent weight of glass cylinder in newtons.
A solid weighs 0.08 kgf in air and 0.065 kgf in water. Find
(1) R.D. of solid
(2) Density of solid in SI system. [Density of water = 1000 kgm3]
A piece of wax floats in brine. What fraction of its volume will be immersed?
R.D. of wax = 0.95, R.D. of brine = 1.1.
A body of volume 100 cm3 weighs 1 kgf in air. Calculate its weight in water. What is its relative density?
