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प्रश्न
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उत्तर
Relative density = density of substance/density of water at 4°C.
As the relative density of platinum is 21.50, this means platinum is 21.5 times denser than water at 4°C.
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संबंधित प्रश्न
A solid of density 5000 kg m-3 weighs 0.5 kgf in air. It is completely immersed in water of density 1000 kg m-3. Calculate the apparent weight of the solid in water.
A body weighs W1gf in air and when immersed in a liquid it weighs W2gf, while it weights W3gf on immersing it in water. Find:
- volume of the body
- upthrust due to liquid
- relative density of the solid
- relative density of the liquid
Relative density of a substance is expressed by comparing the density of that substance with the density of :
The unit of relative density is :
A solid weighs 1.5 kgf in air and 0.9 kgf in a liquid of density 1.2 × 103 kg m-3. Calculate R. D. of solid.
A stone of density 3000 kgm3 is lying submerged in water of density 1000 kgm3. If the mass of stone in air is 150 kg, calculate the force required to lift the stone. [g = 10 ms2]
A solid of area of cross-section 0.004 m2 and length 0.60 m is completely immersed in water of density 1000 kgm3. Calculate:
- Wt of solid in SI system
- Upthrust acting on the solid in SI system.
- Apparent weight of solid in water.
- Apparent weight of solid in brine solution of density 1050 kgm3.
[Take g = 10 N/kg; Density of solid = 7200 kgm3]
A solid of R.D. 4.2 is found to weigh 0.200 kgf in air. Find its apparent weight in water.
Calculate the mass of a body whose volume is 2m3 and relative density is 0.52.
A body of volume 100 cm3 weighs 1 kgf in air. Calculate its weight in water. What is its relative density?
