हिंदी

A solid weighs 105 kgf in air. When completely immersed in water, it displaces 30,000 cm3 of water, calculate relative density of solid.

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प्रश्न

A solid weighs 105 kgf in air. When completely immersed in water, it displaces 30,000 cm3 of water, calculate relative density of solid.

योग
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उत्तर

Weight of solid in air =105 kgf

Volume of solid = Volume of water displaced = 30000 cm3

= 30000 x 10-6 m3 = 0.03 m3

pw = Density of water = 1000 kgm-3

Wt. of water displaced by solid.

`"V"rho_"w""g" = 0.03 xx 1000 xx "g" = 30 "kgf"`

R.D. of solid = `"Weight of solid in air"/"Weight of water displaced by solid"`

`= 105/30 = 3.5`

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Determination of Relative Density of a Solid Substance by Archimedes’ Principle
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Upthrust and Archimedes’ Principle - Subjective Questions

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गोयल ब्रदर्स प्रकाशन A New Approach to ICSE Physics Part 1 [English] Class 9
अध्याय 5 Upthrust and Archimedes’ Principle
Subjective Questions | Q 11

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