Advertisements
Advertisements
प्रश्न
A piece of metal weighs 44.5 gf in air, 39.5 gf in water. What is the R.D. of the metal?
Advertisements
उत्तर
Piece of metal weighs in air = 44.5 f
Piece of metal weighs in liquid = 39.5 f.
Loss of weight of metal in liquid = 44.5 - 39.5 = 5f.
Relative density = weight of solid in air/ loss of weight of solid in water.
Relative density of liquid =44.5f/5f =8.9
Relative density of liquid = 8.9
APPEARS IN
संबंधित प्रश्न
Differentiate between density and relative density of a substance.
The relative density of mercury is 13.6. State its density in
(i) C.G.S. unit and
(ii) S.I. unit.
The density of iron is 7.8 x 103 kg m-3. What is its relative density?
The relative density of silver is 10.8. Find its density.
Calculate the mass of a body whose volume is 2 m3 and relative density is 0.52.
A body of volume 100 cm3 weighs 1 kgf in air. Find:
- Its weight in water and
- Its relative density.
A solid of density 7600 kgm3 is found to weigh 0.950 kgf in air. If 4/5 volume of solid is completely immersed in a solution of density 900 kgm3, find the apparent weight of solid in a liquid.
A solid weighs 0.08 kgf in air and 0.065 kgf in water. Find
(1) R.D. of solid
(2) Density of solid in SI system. [Density of water = 1000 kgm3]
Calculate the mass of a body whose volume is 2m3 and relative density is 0.52.
