Advertisements
Advertisements
प्रश्न
A piece of metal weighs 44.5 gf in air, 39.5 gf in water. What is the R.D. of the metal?
Advertisements
उत्तर
Piece of metal weighs in air = 44.5 f
Piece of metal weighs in liquid = 39.5 f.
Loss of weight of metal in liquid = 44.5 - 39.5 = 5f.
Relative density = weight of solid in air/ loss of weight of solid in water.
Relative density of liquid =44.5f/5f =8.9
Relative density of liquid = 8.9
APPEARS IN
संबंधित प्रश्न
A body of volume V and density ρ is kept completely immersed in a liquid of density ρL. If g is the acceleration due to gravity, then write expressions for the following:
(i) The weight of the body, (ii) The upthrust on the body,
(iii) The apparent weight of the body in liquid, (iv) The loss in weight of the body.
How does the density of material of a body determine whether it will float or sink in water?
The density of iron is 7.8 x 103 kg m-3. What is its relative density?
The relative density of silver is 10.8. Find its density.
Calculate the mass of a body whose volume is 2 m3 and relative density is 0.52.
A solid weighs 32 gf in air and 28.8 gf in water. Find: (i) The volume of solid, (ii) R.D. of solid and (iii) The weight of solid in a liquid of density 0.9 g cm-3.
A solid of density 7600 kgm3 is found to weigh 0.950 kgf in air. If 4/5 volume of solid is completely immersed in a solution of density 900 kgm3, find the apparent weight of solid in a liquid.
A solid weighs 0.08 kgf in air and 0.065 kgf in water. Find
(1) R.D. of solid
(2) Density of solid in SI system. [Density of water = 1000 kgm3]
A body of volume 100 cm3 weighs 1 kgf in air. Calculate its weight in water. What is its relative density?
