Advertisements
Advertisements
प्रश्न
A body of volume 100 cm3 weighs 1 kgf in air. Calculate its weight in water. What is its relative density?
Advertisements
उत्तर
Volume of body= 100 cm3 .
Weight of body= 1 kgf = 1000 gf
Mass of body= 1000 gm.
Density of liquid= 1000 gm/100cm3 = 10 gcm3 .
Density of water at 4° = 1 gcm-3 .
Relative density= density of substance/density of water at 4° C
Relative density = 10 gcm3 / 1 gcm3 = 10
Mass of body= 1000 gm.
Densityofwater = 1 g cm-3
Acceleration due to gravity = 10 ms-2
Upthrust = V x p xg.
Upthrust = 100 x 1 xf = 100 gf.
Resultant weight of the body = weight-upthrust = 1000 gf-100 gf = 900 gf.
APPEARS IN
संबंधित प्रश्न
A sphere of iron and another sphere of wood of the same radius are held under water. Compare the upthrust on the two spheres.
[Hint: Both have equal volume inside the water].
A solid of density 5000 kg m-3 weighs 0.5 kgf in air. It is completely immersed in water of density 1000 kg m-3. Calculate the apparent weight of the solid in water.
Complete the following sentence.
S.I. unit of density is .......... .
What is the unit of relative density?
Differentiate between density and relative density of a substance.
Relative density of a substance is expressed by comparing the density of that substance with the density of :
A stone of density 3000 kgm3 is lying submerged in water of density 1000 kgm3. If the mass of stone in air is 150 kg, calculate the force required to lift the stone. [g = 10 ms2]
A glass cylinder of length 12 x 10-2 m and area of crosssection 5 x 10-4 m2 has a density of 2500 kgm-3. It is immersed in a liquid of density 1500 kgm-3, such that 3/8. of its length is above the liquid. Find the apparent weight of glass cylinder in newtons.
A solid weighs 0.08 kgf in air and 0.065 kgf in water. Find
(1) R.D. of solid
(2) Density of solid in SI system. [Density of water = 1000 kgm3]
An aluminium cube of side 5 cm and RD. 2.7 is suspended by a thread in alcohol of relative density 0.80. Find the tension in thread.
