मराठी

A piece of wax floats in brine. What fraction of its volume will be immersed?R.D. of wax = 0.95, R.D. of brine = 1.1.

Advertisements
Advertisements

प्रश्न

A piece of wax floats in brine. What fraction of its volume will be immersed?
R.D. of wax = 0.95, R.D. of brine = 1.1.

टीपा लिहा
Advertisements

उत्तर

Relative density of wax = 0.95
Relative density of brine = 1.1
(Density of wax/ Density of brine) = fraction submerged
0.95/1.1 = fraction of volume submerged
Fraction of volume submerged = 0.86

shaalaa.com
Determination of Relative Density of a Solid Substance by Archimedes’ Principle
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 4: Fluids - Exercise 2 [पृष्ठ १७४]

APPEARS IN

फ्रँक Physics [English] Class 9 ICSE
पाठ 4 Fluids
Exercise 2 | Q 27 | पृष्ठ १७४

संबंधित प्रश्‍न

A body of volume V and density ρ is kept completely immersed in a liquid of density ρL. If g is the acceleration due to gravity, then write expressions for the following:

(i) The weight of the body, (ii) The upthrust on the body,

(iii) The apparent weight of the body in liquid, (iv) The loss in weight of the body. 


Complete the following sentence.

S.I. unit of density is .......... .


A piece of stone of mass 15.1 g is first immersed in a liquid and it weighs 10.9 gf. Then on immersing the piece of stone in water, it weighs 9.7 gf. Calculate:

  1. The weight of the piece of stone in air,
  2. The volume of the piece of stone,
  3. The relative density of stone,
  4. The relative density of the liquid.

A solid weighs 1.5 kgf in air and 0.9 kgf in a liquid of density 1.2 × 103 kg m-3. Calculate R. D. of solid. 


A solid weighs 120 gf in air and and 105 gf when it is completely immersed in water. Calculate the relative density of solid. 


A solid of area of cross-section 0.004 m2 and length 0.60 m is completely immersed in water of density 1000 kgm3. Calculate:

  1. Wt of solid in SI system
  2. Upthrust acting on the solid in SI system.
  3. Apparent weight of solid in water.
  4. Apparent weight of solid in brine solution of density 1050 kgm3.
    [Take g = 10 N/kg; Density of solid = 7200 kgm3]

A solid of density 7600 kgm3 is found to weigh 0.950 kgf in air. If 4/5 volume of solid is completely immersed in a solution of density 900 kgm3, find the apparent weight of solid in a liquid.


The R.D. of ice is 0.92 and that of sea water is 1.025. Find the total volume of an iceberg which floats with its volume 800 cm3 above water.

A body of mass 70 kg, when completely immersed in water, displaces 20,000 cm3 of water. Find the relative density of the material of the body.

A piece of metal weighs 44.5 gf in air, 39.5 gf in water. What is the R.D. of the metal?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×