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प्रश्न
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उत्तर
When a body is completely immersed in water then it displaces an equal volume of water to its own weight.
So, the volume of the body = 20000 cm3.
Mass of body = 70 kg = 70000 gm
Density of body = mass /volume = 70000/20000= 3.5 gm cm-3.
Density of water in C.G.S system = 1g cm-3.
Relative density of body = density of body /density of water =3.5 gm cm-3/1g cm-3.
Relative density = 3.5.
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संबंधित प्रश्न
What do you understand by the term relative density of a substance?
Relative density of a substance is expressed by comparing the density of that substance with the density of :
A piece of stone of mass 15.1 g is first immersed in a liquid and it weighs 10.9 gf. Then on immersing the piece of stone in water, it weighs 9.7 gf. Calculate:
- The weight of the piece of stone in air,
- The volume of the piece of stone,
- The relative density of stone,
- The relative density of the liquid.
A body of mass 70 kg, when completely immersed in water, displaces 20,000 cm3 of water. Find: (i) The weight of body in water and (ii) The relative density of material of the body.
A solid of R.D. = 2.5 is found to weigh 0.120 kgf in water. Find the wt. of solid in air.
A solid of R.D. 4.2 is found to weigh 0.200 kgf in air. Find its apparent weight in water.
A cylinder made of copper and aluminium floats in mercury of density 13.6 gem-3, such that 0.26th part of it is below mercury. Find the density of solid.
A piece of metal weighs 44.5 gf in air, 39.5 gf in water. What is the R.D. of the metal?
A body of volume 100 cm3 weighs 1 kgf in air. Calculate its weight in water. What is its relative density?
