मराठी

An iceberg floats in sea water of density 1.17 g cm 3, such that 2/9 of its volume is above sea water. Find the density of iceberg. - Physics

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प्रश्न

An iceberg floats in sea water of density 1.17 g cm 3, such that 2/9 of its volume is above sea water. Find the density of iceberg.

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उत्तर

Density of sea water =ρw = 1.17 g cm-3

Density of solid ice berg =ρi = ?

`2/9`th volume of an iceberg is above the seawater

∴ Volume of iceberg inside water = `"V"_"i" = (1 - 2/9)"V"`

Where V = Total volume of an iceberg

`=> "V"_"i" = (9 - 2)/9"V" = 7/9"V"`

⇒ Volume of sea water displaced by immersed part of the iceberg

`= "V"_"w" = 7/9"V"`

By law of floatation:

Weight of iceberg = Weight of sea water displaced by iceberg

`"V"_"i" xx rho_"i" xx "g" = "V"_"w" xx rho_"w" xx "g"`

`"V" xx rho_"i" = 7/9 "V" xx 1.17`

`=> rho_"i" = 7/9 xx 1.17 = 0.91 "gcm"^-3`

⇒ Density of iceburg = 0.91 g cm-3 

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Determination of Relative Density of a Solid Substance by Archimedes’ Principle
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पाठ 5: Upthrust and Archimedes’ Principle - Practice Problems 2

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