Advertisements
Advertisements
प्रश्न
A solid weighs 1.5 kgf in air and 0.9 kgf in a liquid of density 1.2 × 103 kg m-3. Calculate R. D. of solid.
Advertisements
उत्तर
Weight of body in air , W1 = 1.5 kgf
Weight of body when completely immersed in liquid W2 = 0.9 kgf
Density of liquid = 1.2 × 103 kgm-3
R.D. of liquid = 1.2
R.D. of body = `"W"_1/("W"_1 - "W"_2) xx "R.D. of liquid"`
R.D. of body = `1.5/(1.5 - 0.9) xx 1.2`
R.D. of body = `1.5/0.6 xx 1.2`
R.D. of body = 3
APPEARS IN
संबंधित प्रश्न
A sphere of iron and another of wood, both of same radius are placed on the surface of water. State which of the two will sink? Give a reason for your answer.
The relative density of mercury is 13.6. State its density in
(i) C.G.S. unit and
(ii) S.I. unit.
A body weighs 20 gf in air and 18.0 gf in water. Calculate the relative density of the material of the body.
A body of volume 100 cm3 weighs 1 kgf in air. Find:
- Its weight in water and
- Its relative density.
A cube of the lead of side 8 cm and R.D. 10.6 is suspended from the hook of a spring balance. Find the reading of spring balance. The cube is now completely immersed in sugar solution of R.D. 1.4. Calculate the new reading of spring balance.
A cylinder made of copper and aluminium floats in mercury of density 13.6 gem-3, such that 0.26th part of it is below mercury. Find the density of solid.
A piece of wax floats in brine. What fraction of its volume will be immersed?
R.D. of wax = 0.95, R.D. of brine = 1.1.
A piece of metal weighs 44.5 gf in air, 39.5 gf in water. What is the R.D. of the metal?
