Advertisements
Advertisements
प्रश्न
A solid weighs 1.5 kgf in air and 0.9 kgf in a liquid of density 1.2 × 103 kg m-3. Calculate R. D. of solid.
Advertisements
उत्तर
Weight of body in air , W1 = 1.5 kgf
Weight of body when completely immersed in liquid W2 = 0.9 kgf
Density of liquid = 1.2 × 103 kgm-3
R.D. of liquid = 1.2
R.D. of body = `"W"_1/("W"_1 - "W"_2) xx "R.D. of liquid"`
R.D. of body = `1.5/(1.5 - 0.9) xx 1.2`
R.D. of body = `1.5/0.6 xx 1.2`
R.D. of body = 3
APPEARS IN
संबंधित प्रश्न
A body of volume V and density ρ is kept completely immersed in a liquid of density ρL. If g is the acceleration due to gravity, then write expressions for the following:
(i) The weight of the body, (ii) The upthrust on the body,
(iii) The apparent weight of the body in liquid, (iv) The loss in weight of the body.
What is the unit of relative density?
A solid weighs 32 gf in air and 28.8 gf in water. Find: (i) The volume of solid, (ii) R.D. of solid and (iii) The weight of solid in a liquid of density 0.9 g cm-3.
A body of volume 100 cm3 weighs 1 kgf in air. Find:
- Its weight in water and
- Its relative density.
A solid weighs 0.08 kgf in air and 0.065 kgf in water. Find
(1) R.D. of solid
(2) Density of solid in SI system. [Density of water = 1000 kgm3]
A solid of R.D. = 2.5 is found to weigh 0.120 kgf in water. Find the wt. of solid in air.
An iceberg floats in sea water of density 1.17 g cm 3, such that 2/9 of its volume is above sea water. Find the density of iceberg.
Calculate the mass of a body whose volume is 2m3 and relative density is 0.52.
