Advertisements
Advertisements
प्रश्न
A solid of R.D. = 2.5 is found to weigh 0.120 kgf in water. Find the wt. of solid in air.
Advertisements
उत्तर
Relative density of solid = R.D. = 2.5
Weight of solid in water = W’ = 0.120 kgf
Weight of solid in air = W = ?
R.D. = `"Weight of solid in air"/("wt. of solid in air"-"wt. of solid in water")`
R.D. = `"W"/("W" - "W"')`
2.5 = `"W"/("W" - 0.120)`
2.5 W - 2.5 × 0.120 = W
2.5 W - 0.3 = W
2.5 W - W = 0.3
1.5 W = 0.3
W = `0.3/1.5` = 0.20 kgf
So, weight of solid in air = 0.20 kgf
APPEARS IN
संबंधित प्रश्न
A sphere of iron and another sphere of wood of the same radius are held under water. Compare the upthrust on the two spheres.
[Hint: Both have equal volume inside the water].
How are the (i) Mass, (ii) Volume and (iii) Density of a metallic piece affected, if at all, with an increase in temperature?
What is the unit of relative density?
The relative density of mercury is 13.6. State its density in
(i) C.G.S. unit and
(ii) S.I. unit.
The density of iron is 7.8 x 103 kg m-3. What is its relative density?
A stone of density 3000 kgm3 is lying submerged in water of density 1000 kgm3. If the mass of stone in air is 150 kg, calculate the force required to lift the stone. [g = 10 ms2]
A solid of R.D. 4.2 is found to weigh 0.200 kgf in air. Find its apparent weight in water.
A solid weighs 105 kgf in air. When completely immersed in water, it displaces 30,000 cm3 of water, calculate relative density of solid.
Calculate the mass of a body whose volume is 2m3 and relative density is 0.52.
