Advertisements
Advertisements
Question
A solid of R.D. = 2.5 is found to weigh 0.120 kgf in water. Find the wt. of solid in air.
Advertisements
Solution
Relative density of solid = R.D. = 2.5
Weight of solid in water = W’ = 0.120 kgf
Weight of solid in air = W = ?
R.D. = `"Weight of solid in air"/("wt. of solid in air"-"wt. of solid in water")`
R.D. = `"W"/("W" - "W"')`
2.5 = `"W"/("W" - 0.120)`
2.5 W - 2.5 × 0.120 = W
2.5 W - 0.3 = W
2.5 W - W = 0.3
1.5 W = 0.3
W = `0.3/1.5` = 0.20 kgf
So, weight of solid in air = 0.20 kgf
APPEARS IN
RELATED QUESTIONS
A sphere of iron and another of wood, both of same radius are placed on the surface of water. State which of the two will sink? Give a reason for your answer.
How are the (i) Mass, (ii) Volume and (iii) Density of a metallic piece affected, if at all, with an increase in temperature?
What is the unit of relative density?
Calculate the mass of a body whose volume is 2 m3 and relative density is 0.52.
A piece of stone of mass 15.1 g is first immersed in a liquid and it weighs 10.9 gf. Then on immersing the piece of stone in water, it weighs 9.7 gf. Calculate:
- The weight of the piece of stone in air,
- The volume of the piece of stone,
- The relative density of stone,
- The relative density of the liquid.
A body weighs 20 gf in air and 18.0 gf in water. Calculate the relative density of the material of the body.
A body of mass 70 kg, when completely immersed in water, displaces 20,000 cm3 of water. Find: (i) The weight of body in water and (ii) The relative density of material of the body.
A cube of the lead of side 8 cm and R.D. 10.6 is suspended from the hook of a spring balance. Find the reading of spring balance. The cube is now completely immersed in sugar solution of R.D. 1.4. Calculate the new reading of spring balance.
Calculate the mass of a body whose volume is 2m3 and relative density is 0.52.
