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A Body of Mass 70 Kg, When Completely Immersed in Water, Displaces 20,000 Cm3 Of Water. Find: (I) the Weight of Body in Water and (Ii) the Relative Density of Material of the Body. - Physics

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Question

A body of mass 70 kg, when completely immersed in water, displaces 20,000 cm3 of water. Find: (i) The weight of body in water and (ii) The relative density of material of the body. 

Sum
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Solution

Weight of body = 70 kg

Volume of water displaced by body = 20,000 cm3 = 0.02 m3

(i) Mass  of solid immersed in water = mass of water displaced

Mass of solid immersed in water = Density of water × Volume of water displaced

Mass of solid immersed in water = 1000 × 0.02 = 20 kg

Weight of the body, W=mg

Weight of the body in water =(70×9.8)−(20×9.8)=50 kgf

 

(ii) R.D. of solid = Density in C.G.S. (without unit)

Density in C.G.S. = `"mass"/"volume" = (70 xx 1000)/(20,000) = 3.5` gcm3

R.D. = 3.5

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Determination of Relative Density of a Solid Substance by Archimedes’ Principle
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Chapter 5: Upthrust in Fluids, Archimedes’ Principle and Floatation - Exercise 5 (B) [Page 117]

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Selina Concise Physics [English] Class 9 ICSE
Chapter 5 Upthrust in Fluids, Archimedes’ Principle and Floatation
Exercise 5 (B) | Q 9 | Page 117

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