हिंदी

A Body of Mass 70 Kg, When Completely Immersed in Water, Displaces 20,000 Cm3 Of Water. Find: (I) the Weight of Body in Water and (Ii) the Relative Density of Material of the Body.

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प्रश्न

A body of mass 70 kg, when completely immersed in water, displaces 20,000 cm3 of water. Find: (i) The weight of body in water and (ii) The relative density of material of the body. 

योग
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उत्तर

Weight of body = 70 kg

Volume of water displaced by body = 20,000 cm3 = 0.02 m3

(i) Mass  of solid immersed in water = mass of water displaced

Mass of solid immersed in water = Density of water × Volume of water displaced

Mass of solid immersed in water = 1000 × 0.02 = 20 kg

Weight of the body, W=mg

Weight of the body in water =(70×9.8)−(20×9.8)=50 kgf

 

(ii) R.D. of solid = Density in C.G.S. (without unit)

Density in C.G.S. = `"mass"/"volume" = (70 xx 1000)/(20,000) = 3.5` gcm3

R.D. = 3.5

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Determination of Relative Density of a Solid Substance by Archimedes’ Principle
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Upthrust in Fluids, Archimedes’ Principle and Floatation - Exercise 5 (B) [पृष्ठ ११७]

APPEARS IN

सेलिना Concise Physics [English] Class 9 ICSE
अध्याय 5 Upthrust in Fluids, Archimedes’ Principle and Floatation
Exercise 5 (B) | Q 9 | पृष्ठ ११७

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