Advertisements
Advertisements
प्रश्न
A body of mass 70 kg, when completely immersed in water, displaces 20,000 cm3 of water. Find: (i) The weight of body in water and (ii) The relative density of material of the body.
Advertisements
उत्तर
Weight of body = 70 kg
Volume of water displaced by body = 20,000 cm3 = 0.02 m3
(i) Mass of solid immersed in water = mass of water displaced
Mass of solid immersed in water = Density of water × Volume of water displaced
Mass of solid immersed in water = 1000 × 0.02 = 20 kg
Weight of the body, W=mg
Weight of the body in water =(70×9.8)−(20×9.8)=50 kgf
(ii) R.D. of solid = Density in C.G.S. (without unit)
Density in C.G.S. = `"mass"/"volume" = (70 xx 1000)/(20,000) = 3.5` gcm3
R.D. = 3.5
APPEARS IN
संबंधित प्रश्न
A sphere of iron and another of wood, both of same radius are placed on the surface of water. State which of the two will sink? Give a reason for your answer.
A solid of density 5000 kg m-3 weighs 0.5 kgf in air. It is completely immersed in water of density 1000 kg m-3. Calculate the apparent weight of the solid in water.
Complete the following sentence.
Density in kg m-3 = ............ × density in g cm-3
What do you understand by the term relative density of a substance?
A body weighs 20 gf in air and 18.0 gf in water. Calculate the relative density of the material of the body.
A solid of area of cross-section 0.004 m2 and length 0.60 m is completely immersed in water of density 1000 kgm3. Calculate:
- Wt of solid in SI system
- Upthrust acting on the solid in SI system.
- Apparent weight of solid in water.
- Apparent weight of solid in brine solution of density 1050 kgm3.
[Take g = 10 N/kg; Density of solid = 7200 kgm3]
A solid weighs 0.08 kgf in air and 0.065 kgf in water. Find
(1) R.D. of solid
(2) Density of solid in SI system. [Density of water = 1000 kgm3]
A cylinder made of copper and aluminium floats in mercury of density 13.6 gem-3, such that 0.26th part of it is below mercury. Find the density of solid.
