Advertisements
Advertisements
प्रश्न
A body of volume 100 cm3 weighs 1 kgf in air. Calculate its weight in water. What is its relative density?
Advertisements
उत्तर
Volume of body= 100 cm3 .
Weight of body= 1 kgf = 1000 gf
Mass of body= 1000 gm.
Density of liquid= 1000 gm/100cm3 = 10 gcm3 .
Density of water at 4° = 1 gcm-3 .
Relative density= density of substance/density of water at 4° C
Relative density = 10 gcm3 / 1 gcm3 = 10
Mass of body= 1000 gm.
Densityofwater = 1 g cm-3
Acceleration due to gravity = 10 ms-2
Upthrust = V x p xg.
Upthrust = 100 x 1 xf = 100 gf.
Resultant weight of the body = weight-upthrust = 1000 gf-100 gf = 900 gf.
APPEARS IN
संबंधित प्रश्न
A metal cube of edge 5 cm and density 9 g cm-3 is suspended by a thread so as to be completely immersed in a liquid of density 1.2 g cm-3. Find the tension in thread. (Take g = 10 m s-2)
Complete the following sentence.
Density in kg m-3 = ............ × density in g cm-3
Differentiate between density and relative density of a substance.
The relative density of mercury is 13.6. State its density in
(i) C.G.S. unit and
(ii) S.I. unit.
Calculate the mass of a body whose volume is 2 m3 and relative density is 0.52.
A piece of stone of mass 113 g sinks to the bottom in water contained in a measuring cylinder and water level in cylinder rises from 30 ml to 40 ml. Calculate R.D. of stone.
A body of volume 100 cm3 weighs 1 kgf in air. Find:
- Its weight in water and
- Its relative density.
A body of mass 70 kg, when completely immersed in water, displaces 20,000 cm3 of water. Find: (i) The weight of body in water and (ii) The relative density of material of the body.
A glass cylinder of length 12 x 10-2 m and area of crosssection 5 x 10-4 m2 has a density of 2500 kgm-3. It is immersed in a liquid of density 1500 kgm-3, such that 3/8. of its length is above the liquid. Find the apparent weight of glass cylinder in newtons.
