Advertisements
Advertisements
Question
A body of volume 100 cm3 weighs 1 kgf in air. Calculate its weight in water. What is its relative density?
Advertisements
Solution
Volume of body= 100 cm3 .
Weight of body= 1 kgf = 1000 gf
Mass of body= 1000 gm.
Density of liquid= 1000 gm/100cm3 = 10 gcm3 .
Density of water at 4° = 1 gcm-3 .
Relative density= density of substance/density of water at 4° C
Relative density = 10 gcm3 / 1 gcm3 = 10
Mass of body= 1000 gm.
Densityofwater = 1 g cm-3
Acceleration due to gravity = 10 ms-2
Upthrust = V x p xg.
Upthrust = 100 x 1 xf = 100 gf.
Resultant weight of the body = weight-upthrust = 1000 gf-100 gf = 900 gf.
APPEARS IN
RELATED QUESTIONS
A solid of density 5000 kg m-3 weighs 0.5 kgf in air. It is completely immersed in water of density 1000 kg m-3. Calculate the apparent weight of the solid in water.
How are the (i) Mass, (ii) Volume and (iii) Density of a metallic piece affected, if at all, with an increase in temperature?
Relative density of a substance is expressed by comparing the density of that substance with the density of :
The unit of relative density is :
A body weighs 20 gf in air and 18.0 gf in water. Calculate the relative density of the material of the body.
A solid weighs 120 gf in air and and 105 gf when it is completely immersed in water. Calculate the relative density of solid.
A body of volume 100 cm3 weighs 1 kgf in air. Find:
- Its weight in water and
- Its relative density.
A stone of density 3000 kgm3 is lying submerged in water of density 1000 kgm3. If the mass of stone in air is 150 kg, calculate the force required to lift the stone. [g = 10 ms2]
A solid of R.D. 4.2 is found to weigh 0.200 kgf in air. Find its apparent weight in water.
