Advertisements
Advertisements
प्रश्न
A body weighs 20 gf in air and 18.0 gf in water. Calculate the relative density of the material of the body.
Advertisements
उत्तर
Weight of body in air , W1 = 20 gf
Weight of body when completely immersed in water W2 = 18 gf
R.D. of body = `W_1/(W_1 - W_2) xx "R.D. of water"`
R.D. of body = `20/(20 - 18) xx 1`
R.D. of body = 10
APPEARS IN
संबंधित प्रश्न
Complete the following sentence.
S.I. unit of density is .......... .
What is the unit of relative density?
A stone of density 3000 kgm3 is lying submerged in water of density 1000 kgm3. If the mass of stone in air is 150 kg, calculate the force required to lift the stone. [g = 10 ms2]
A glass cylinder of length 12 x 10-2 m and area of crosssection 5 x 10-4 m2 has a density of 2500 kgm-3. It is immersed in a liquid of density 1500 kgm-3, such that 3/8. of its length is above the liquid. Find the apparent weight of glass cylinder in newtons.
A solid weighs 0.08 kgf in air and 0.065 kgf in water. Find
(1) R.D. of solid
(2) Density of solid in SI system. [Density of water = 1000 kgm3]
A solid of R.D. 4.2 is found to weigh 0.200 kgf in air. Find its apparent weight in water.
An aluminium cube of side 5 cm and RD. 2.7 is suspended by a thread in alcohol of relative density 0.80. Find the tension in thread.
A cylinder made of copper and aluminium floats in mercury of density 13.6 gem-3, such that 0.26th part of it is below mercury. Find the density of solid.
A body of volume 100 cm3 weighs 1 kgf in air. Calculate its weight in water. What is its relative density?
