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प्रश्न
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उत्तर
Relative density of Ice = 0.92
Relative density of sea water = 1.025
Let the total volume of iceberg = X cm3.
The volume of the iceberg above water = 800 cm3.
The volume of the iceberg is submerged in the water = (X - 800) cm3.
Fraction of iceberg submerged = (X- 800)/X
Now we know that the fractional part submerged equals the ratio of the density of the material of the block to the density of the liquid.
(Density of ice / Density of sea water) = fraction submerged
0.92/1.025 = (X-800)/X
0.8975 X = X - 800
X - 0.8975 X = 800
0.1025 X = 800
X = 800/0.1025 = 7804.8 cm3.
Total volume of iceberg = 7804.8 cm3.
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